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eimsori [14]
3 years ago
8

Can anyone help please right answer only

Mathematics
1 answer:
BARSIC [14]3 years ago
7 0

The value of x is 27°.

Solution:

Given \triangle \mathrm{ACB} \cong \Delta \mathrm{DCE}.

∠A = 3x – 10, ∠C = 45°, ∠D = 2x + 10

<em>If two triangles are congruent, then the angles are congruent.</em>

∠A = ∠E (Alternate interior angles)

∠C = ∠C (Reflexive property)

∠B = ∠D (Alternative interior angles)

⇒ ∠B = 2x + 10

<em>Sum of the interior angles of the triangle = 180°</em>

In ΔACB,

3x – 10 + 45° + 2x + 10 = 180°

5x + 45° = 180°

Subtract 45° on both sides of the equation.

5x = 135°

Divide by 5 on both sides of the equation.

x = 27°

The value of x is 27°.

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