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disa [49]
3 years ago
8

4 1/5 - 2 7/10 ________

Mathematics
2 answers:
ZanzabumX [31]3 years ago
5 0
11/2 also download Socratic it is great math help/answers
notsponge [240]3 years ago
3 0
15/10 which equals 1 5/10 which equals 1 1/2
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Please help asap calculate the slope of the line through the points (6,-8) and (3,-4).
Taya2010 [7]

Answer:

Step-by-step explanation:

Mathematically, we can calculate the slope

using the formula below;

m = (y2-y1)/(x2-x1)

Where (x1.y1) = (6,-8)

(x2, y2) = (3,-4)

So inputing these values into the formula, we have

m = (-4-(-8))/(3-6)

m = (-4+8)/-3 = 4/-3 = -4/3

Now, we want to write the equation of the line;

y= -4/3x + c

to get the value of c, we simply need to use any of the points. We use any of the two points by substituting the values of x and y at that point.

Let’s use (3,-4)

That would give ;

-4 = -4/3(3) + c

-4 = -4 + c

This means c = 0

Thus the equation of the line is y = -4/3x

Now to find out if the point (-3,4) is on the line

We only need to substitute the values of x and y here and see ;

Thus;

4 = -4/3(-3)

Sine 4 = 4

We can conclude that the point is on the line in question

7 0
4 years ago
The lengths of the sides of a triangle are 17, 8 and n. Which of the following must be true
Taya2010 [7]
N is either 17 or 8.
3 0
4 years ago
The volume of an oblique pyramid with a square base is V units3 and the height is h units. Which expression represents the area
givi [52]

Answer:

Area of the base of the pyramid = V/h

Step-by-step explanation:

Mathematically, we know that the volume of the pyramid can be calculated by multiplying the area of the base by the height of the pyramid

Now using the variables in the question;

V = area of base * height of pyramid

Area of base = V/height of pyramid

Area of base = V/h

3 1
3 years ago
What happens to ice as it melts
Ludmilka [50]
It becomes a liquid
hope this helped
3 0
3 years ago
Read 2 more answers
Consider the line y=1 x -1 and the point P=(2,0).
Montano1993 [528]

Answer:

Step-by-step explanation:

d(x)=√((x-2)2+(y-0)²)

=√((x-2)²+y²)

=√((x-2)²+(x-1)²)

=√(x²-4x+4+x²-2x+1)

=√(2x²-6x+5)

D=d²(x)=2x²-6x+5

b.\\\frac{dD}{dx}=4x-6\\\frac{dD}{dx}=0,gives \\4x-6=0\\x=\frac{3}{2}\\\frac{d^2D}{dx^2}=4 >0 at x=\frac{3}{2}\\so~D~or~d^2~or~d~is~minimum~at~x=\frac{3}{2}\\so~y=1(\frac{3}{2} )-1=1/2=0.5\\so~nearest~point~is~(1.5,0.5)

8 0
3 years ago
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