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3 years ago

Helppppppppppppppppp

Mathematics

2 answers:

Usimov [2.4K]3 years ago

5 0

1over 2 division the number

kramer3 years ago

3 0

The answer is 2/3 hope this helps
/ = fraction

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Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of

tresset_1 [31]

Because I've gone ahead with trying to parameterize $S$ directly and learned the hard way that the resulting integral is large and annoying to work with, I'll propose a less direct approach.

Rather than compute the surface integral over $S$ straight away, let's close off the hemisphere with the disk $D$ of radius 9 centered at the origin and coincident with the plane $y=0$ . Then by the divergence theorem, since the region $S\cup D$ is closed, we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV$

where $R$ is the interior of $S\cup D$ . $\vec F$ has divergence

$\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(xz)}{\partial x}+\dfrac{\partial(x)}{\partial y}+\dfrac{\partial(y)}{\partial z}=z$

so the flux over the closed region is

$\displaystyle\iiint_Rz\,\mathrm dV=\int_0^\pi\int_0^\pi\int_0^9\rho^3\cos\varphi\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=0$

The total flux over the closed surface is equal to the flux over its component surfaces, so we have

$\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iint_S\vec F\cdot\mathrm d\vec S+\iint_D\vec F\cdot\mathrm d\vec S=0$

$\implies\boxed{\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=-\iint_D\vec F\cdot\mathrm d\vec S}$

Parameterize $D$ by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec k$

with $0\le u\le9$ and $0\le v\le2\pi$ . Take the normal vector to $D$ to be

$\vec s_u\times\vec s_v=-u\,\vec\jmath$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^9(u^2\cos v\sin v\,\vec\imath+u\cos v\,\vec\jmath)\cdot(-u\,\vec\jmath)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{2\pi}\int_0^9u^2\cos v\,\mathrm du\,\mathrm dv=0$

$\implies\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\boxed{0}$

8 0

3 years ago

Please help me with this question

Bezzdna [24]

Answer:

1.03

Step-by-step explanation:

To find the volume of a prism, find the area of the base and multiply it by the height.

The base is an octagon. The area is found $A = 2(1+\sqrt{2})a^2$ . Substitute a = 0.5.

$A = 2(1+\sqrt{2})(0.5^2)\\A = 4.828...(0.25)\\A = 1.21$

The volume is 1.21*2.5 = 3.025.

However, there are three holes drilled out half way which each have volume 0.06.

The volume is found as V = πr²h. Substitute r = 0.125 which is half the diameter of 0.25. Since they go half way, the height is h = 1.25.

V = π(0.125)²(1.25) = 0.06.

Since there are 3, they equal 3*0.06 = 0.18.

Subtract this from the volume.

1.21 - 0.18 = 1.03

4 0

3 years ago

Check 8.0622577483 rounded to the nearest tenth <br> = 8.1 <br> Is that correct

alisha [4.7K]

Yes that it's correct because numbers that are 5+ round up and numbers that are 4-stay the same.

6 0

3 years ago

Read 2 more answers

Please help and thank you

zubka84 [21]

Answer:

Step-by-step explanation:

The graph of x² is known as the parent function. From it, all quadratics can be transformed to make their graphs. It can undergo a series of transformations like translations up/down/left/right or stretch and compression vertically and horizontally. Usually the equation can tell you you what transformations it undergoes. Since g(x) is the same equation as x² except for 4/5 this is a vertical compression. Since it is the leading coefficient under multiplication and 4/5 < 1, this is a compression vertically. Answer B is correct.

8 0

3 years ago

Graph y=3/4x-4 pls helppppppp.......,,,,,,,,,,.,,,,,

boyakko [2]

Step-by-step explanation:

Plug in y=3/4x-4 into desmos :)

7 0

3 years ago

Read 2 more answers