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finlep [7]
3 years ago
5

Factor the polynomial completely. 12x4 – 42x3 – 90x2 What is the GCF of the polynomial? 3 3x 6x 6x2

Mathematics
2 answers:
kupik [55]3 years ago
4 0

Answer:

D) 6x^{2}

Step-by-step explanation:

edu2020

Otrada [13]3 years ago
3 0

Answer:

DDDDDDDD

Step-by-step explanation:

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3 years ago
A tree initially measured 3812 feet tall. Over the next 512 years, it grew to a final height of 4912 feet. During those 512 year
Arlecino [84]

Answer:

2 feet per year

Step-by-step explanation:

I think you meant 38 1/2

and 5 1/2

but if you didn't then its

2.1484375

because

4912-3812=1100

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3 0
3 years ago
The figure below is made out of rectangles what is the perimeter of the figure below note that not all the side links are labele
Vladimir [108]

Answer:

Perimeter of the figure = 24 m.

Step-by-step explanation:

The given figure is a square of side 6 m in which a rectangle of length 4 m and width 2 m is cut at the corner.

Therefore, the missing sides are 6-4 = 2 m and 6-2 = 4 m.

Hence, the perimeter of the figure = 6 + 6 + 2 + 2 + 4 + 4 = 24 m.

3 0
3 years ago
On tax free weekend Michael bought 3 shirts that cost $19.50 each. He used a coupon for 25% off of the total purchase. Rounded t
trasher [3.6K]
His total would be 58.50 then you multiply by .25 percent then you take 14.63 and subtract that from the total and you get 43.87
8 0
3 years ago
Please someone help me to prove this. ​
dem82 [27]
<h3><u>Answer</u> :</h3>

We know that,

\dag\bf\:sin^2A=\dfrac{1-cos2A}{2}

\dag\bf\:sin2A=2sinA\:cosA

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

<u>Now, Let's solve</u> !

\leadsto\:\bf\dfrac{sin^2A-sin^2B}{sinA\:cosA-sinB\:cosB}

\leadsto\:\sf\dfrac{\frac{1-cos2A}{2}-\frac{1-cos2B}{2}}{\frac{2sinA\:cosA}{2}-\frac{2sinB\:cosB}{2}}

\leadsto\:\sf\dfrac{1-cos2A-1+cos2B}{sin2A-sin2B}

\leadsto\:\sf\dfrac{2sin\frac{2A+2B}{2}\:sin\frac{2A-2B}{2}}{2sin\frac{2A-2B}{2}\:cos\frac{2A+2B}{2}}

\leadsto\:\sf\dfrac{sin(A+B)}{cos(A+B)}

\leadsto\:\bf{tan(A+B)}

5 0
3 years ago
Read 2 more answers
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