No the law of cross cutting relates to all somewhat horizontal. The law of cross cutting is the logical assumption that a magma protrusion that cuts through horizontal layers at a diagonal or vertical is younger than the layers that it cuts through.
Sedimentary rocks are most often found in horizontal or near horizontal layers or strata. Therefore cross cutting can be used most often in the relative dating of sedimentary rocks.
However lava flows also form horizontal layers of rock. Pumice ash can be laid down in horizontal layers. A magma protrusion can also be used to relative date igneous layers of rock
Starting in 1908, while a professor at the University of Chicago, Millikan worked on an oil-drop experiment in which he measured the charge on a single electron. J. J. Thomson had already discovered the charge-to-mass ratio of the electron.
Answer:
63.5474U.M.A. es la masa atómica promedio del cobre
Explanation:
La masa atómica promedio de un átomo es definida como la suma de las masas de los isótopos multiplicada por su abundancia. Para el caso del cobre que tiene dos isótopos:
Cu = Masa 65Cu*Abundancia + Masa 63Cu*Abundancia
Reemplazando con los valores dados en el problema:
Cu = 62.9298U.M.A.*0.6909 + 64.9278U.M.A.*0.3091
Cu = 63.5474U.M.A. es la masa atómica promedio del cobre
Answer: 7 milimoles of dissolve in 1 litre water.
Explanation:
Given: gas is passed through water at 293K.
Assumption : exerts a partial pressure of 0.987 bar.
Take : Henry's constant = 76.8 Kbar
To find : Number of moles of gas dissolve in 1 litre water.
According to Henry's law,
moles in 1 liter of water =
Let n= moles of nitrogen
Total moles = 55.56+n
So,
Hence, 7 milimoles of dissolve in 1 litre water.
Explanation:
kclo3- 39+35.5+16*3=122.5
molar mass = 122.5
mass = 14.0g
volume= 100cm3
solubility in mol/dm3 or molarity = ?
but we know that
no of moles = solubility in mol/dm3×vol in cm3
---------------------------------------------
1000
no of moles = mass
---------
molar mass
mass\molar mass= solubility in mol/dm3 *vol in cm3/ 1000
14.0/122.5=x * 100/1000
solubility =0.875 mol/dm3