Answer:
I think It's C
Explanation:
due to higher waves can get easy transfers and receive those signals for most things, such as radios, TVs, phone signals etc etc
Metalloids are all solid at room temperature<span>. Some metalloids, such as silicon and germanium, can act as </span>electrical<span> conductors under the right conditions, thus they are called semiconductors. Silicon, for example, appears lustrous but is not malleable or </span>ductile<span> (it is brittle - a characteristic of some nonmetals).
If this helped, please give me brainliest :)</span>
Answer: The molecular formula will be ![H_{16}NOCl](https://tex.z-dn.net/?f=H_%7B16%7DNOCl)
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of H = 5.80 g
Mass of N = 20.16 g
Mass of O = 23.02 g
Mass of Cl = 51.02 g
Step 1 : convert given masses into moles.
Moles of H =![\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.80g}{1g/mole}=5.80moles](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B%20given%20mass%20of%20H%7D%7D%7B%5Ctext%7B%20molar%20mass%20of%20H%7D%7D%3D%20%5Cfrac%7B5.80g%7D%7B1g%2Fmole%7D%3D5.80moles)
Moles of N =
Moles of O =![\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{23.02g}{16g/mole}=1.44moles](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B%20given%20mass%20of%20O%7D%7D%7B%5Ctext%7B%20molar%20mass%20of%20O%7D%7D%3D%20%5Cfrac%7B23.02g%7D%7B16g%2Fmole%7D%3D1.44moles)
Moles of Cl =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For H = ![\frac{5.80}{1.44}=4](https://tex.z-dn.net/?f=%5Cfrac%7B5.80%7D%7B1.44%7D%3D4)
For N =
For O = ![\frac{1.44}{1.44}=1](https://tex.z-dn.net/?f=%5Cfrac%7B1.44%7D%7B1.44%7D%3D1)
For Cl =
The ratio of H: N: O: Cl= 4: 1: 1: 1
Hence the empirical formula is
The empirical weight of
= 4(1)+1(14)+ 1(16) + 1(35.5)= 69.5 g.
The molecular weight = 278 g/mole
Now we have to calculate the molecular formula.
The molecular formula will be=![4\times H_4NOCl=H_{16}NOCl](https://tex.z-dn.net/?f=4%5Ctimes%20H_4NOCl%3DH_%7B16%7DNOCl)
Answer:
V/V% = 8.2%
Explanation:
Given data:
Volume of methanol = 37.5 mL
Volume of solution = 456 mL
V/V% = ?
Solution:
V/V% = [volume of solute / volume of solution ]×100
V/V% = 37.5 mL / 456 mL × 100
V/V% = 0.08× 100
V/V% = 8.2%
Answer:
2.6 kJ
Explanation:
The formula for the amount of heat (q) absorbed by the water is
q = mCΔT
1. Calculate ΔT
ΔT = 23.5 °C - 22.1 °C = 1.4 °C
2. Calculate q
q₂ = mCΔT = 500 g × 4.184 J·°C⁻¹g⁻¹ × 1.4 °C = 2900 J = 2.9 kJ