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Dafna1 [17]
3 years ago
9

Air is trapped in a cylinder fitted with a piston that occupies 150.5 mL at 1.12 atm pressure. What is the new volume when the p

iston is depressed, increasing the pressure by 15%?
Chemistry
1 answer:
wolverine [178]3 years ago
5 0

Answer:

New volume V2 = 120.4 ml

Explanation:

Given:

Pressure P1 = 1.12 atm

New pressure P2 = 1.12[1+0.25] = 1.4 atm

Old volume V1 = 150.5 ml

Find:

New volume V2

Computation:

P1V1 = P2V2

(1.12)(150.5) = (1.4)(V2)

V2 = 120.4 ml

New volume V2 = 120.4 ml

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Answer:

c

Explanation:

because potential energy is created with the position of a body when you pick up something the thing will have stored energy which is transferred from you so the stored energy is potential energy created by the position of a body that when you see over your head you scared of that thing not to bit you because it has stored energy if you see the thing already failed on the ground you wouldn't scared of that because the enery is already gone

Hope help you

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3 years ago
A scientist adds a liquid to a base. As it is added the substance turns reddish pink the liquid is most likely?
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Answer:

what we need to answer here?

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Woodpeckers find insects to eat by pecking holes in trees with their beaks. One day, a woodpecker finds a particular tree that o
bixtya [17]

Answer:

1. Reflex Conditioning

Explanation:

Conditioning is an aspect of learning where a stimulus works effectively in producing a response from an organism. This response becomes regular given the type of reinforcement that is administered to the organism. The reinforcement is usually a reward that is given to the organism.

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4 0
3 years ago
An experiment shows that a 236 mL gas sample has a mass of 0.443 g at a pressure of 740 mmHg and a temperature of 22 ∘C. What is
aleksley [76]

Answer:

49.2 g/mol

Explanation:

Let's first take account of what we have and convert them into the correct units.

Volume= 236 mL x (\frac{1 L}{1000 mL}) = .236 L

Pressure= 740 mm Hg x (\frac{1 atm}{760 mm Hg})= 0.97 atm

Temperature= 22C + 273= 295 K

mass= 0.443 g

Molar mass is in grams per mole, or MM= \frac{mass}{moles} or MM= \frac{m}{n}. They're all the same.

We have mass (0.443 g) we just need moles. We can find moles with the ideal gas constant PV=nRT. We want to solve for n, so we'll rearrange it to be

n=\frac{PV}{RT}, where R (constant)= 0.082 L atm mol-1 K-1

Let's plug in what we know.

n=\frac{(0.97 atm)(0.236 L)}{(0.082)(295K)}

n= 0.009 mol

Let's look back at MM= \frac{m}{n} and plug in what we know.

MM= \frac{0.443 g}{0.009 mol}

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