Answer is: -601,2 kJ/mol
Chemical reaction: Mg(OH)₂ → MgO + H₂O.
ΔHrxn = 37,5 kJ/mol.
ΔHf(Mg(OH)₂) = <span>−924,5 kJ/mol.
</span>ΔHf(H₂O) = <span>−285,8 kJ/mol.
</span>ΔHrxn -enthalpy of reaction.
ΔHf - enthalpy of formation.
<span>ΔHrxn=∑productsΔHf−∑reactantsΔHf.
</span>ΔHf(MgO) = -924,5 kJ/mol - (-285,8 kJ/mol) + 37,5 kj/mol.
ΔHf(MgO) = -601,2 kJ/mol.
Answer:
1.Magnetosphere
2.Liquid Outer core
3.Atmosphere
4.Lightening
5.Biosphere
6.Blue
7.Dolphins
8.Hydrosphere
9.Ice Caps
10.Lithosphere
11.Latitude
12.Longitude
Explanation:
The invisible field that protect us from solar radiation is called Magnetosphere.
This protective field is created by movement between solid inner core and earth's Liquid outer core.
The layer of gases is called atmosphere.
In addition to wind , rain , lightening is observed on stormy night.
Because of water earth looks Blue.
Dolphins are just one of the animals that calls the hydrosphere, its home.
Ice caps in the north and south poles.
Rocky layer of solid earth is part of Lithosphere.
Look for the latitude first ,horizontal line ...
Explanation:
As density is defined as the mass of a substance divided by its volume.
Mathematically, Density = 
It is given that mass is 50 g and density is 0.934
.
Hence, calculate the volume of methyl acetate as follows.
Density = 
0.934
= 
Volume = 
or, =
(as 1
= 1 mL)
Thus, we can conclude that the volume of methyl acetate the student should pour out is
.
Opp that that person has to correct answer
Answer:
24x10³
Explanation:
2CO₂(g) + 4H₂O(g) → 2CH₃OH(l) + 3O₂ (g)
The equilibrium constant for this reaction is:
Kc = ![\frac{[O_2]^3}{[CO_2]^2[H_2O]^4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BO_2%5D%5E3%7D%7B%5BCO_2%5D%5E2%5BH_2O%5D%5E4%7D)
The expression of [CH₃OH] is left out as it is a pure liquid.
Now we <u>convert the given masses of the relevant species into moles</u>, using their <em>respective molar masses</em>:
- CO₂ ⇒ 3.28 g ÷ 44 g/mol = 0.0745 mol CO₂
- H₂O ⇒ 3.86 g ÷ 18 g/mol = 0.214 mol H₂O
- O₂ ⇒ 2.80 g ÷ 32 g/mol = 0.0875 mol O₂
Then we calculate the concentrations:
- [CO₂] = 0.0745 mol / 7.5 L = 0.0099 M
- [H₂O] = 0.214 mol / 7.5 L = 0.0285 M
- [O₂] = 0.0875 mol / 7.5 L = 0.0117 M
Finally we <u>calculate Kc</u>:
- Kc =
= 24x10³