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3 years ago

GEOMETRY PLEASE HELP ME

Mathematics

1 answer:

castortr0y [4]3 years ago

7 0

I'll go by boxes (top statement box is #1, top reason box is #2, etc.)

If you don't have enough boxes, you can omit (remove) the first 2 I wrote, which is the given

1. 8y = 9x - 14; y = 5
2. Given

3. 8(5) = 9x - 14
4. Substitution

5. 40 = 9x - 14
6. Simplification (or multiplication)

7. 54 = 9x
8. Additive property of equality

9. 6 = x
10. Division property of equality

11. x = 6
12. Symmetrical property of equality

Hope this helps (:

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Jauanita and Keenan own a camping supply store and just put in an order fir flashlights and sleeping bags. The number of flashli

OLEGan [10]

Answer:

85 flashlights
17 sleeping bags

Step-by-step explanation:

One group of 5 flashlights and 1 sleeping bag will cost ...

$12×5 +45 = $105

The total cost of the order is $1785/$105 = 17 times that amount, so there were ...

17 sleeping bags ordered

17×5 = 85 flashlights ordered

3 0

3 years ago

What is the circumference of a circle with a diameter of 72 millimeters?

OlgaM077 [116]

72×3.14=226.08 millimeters

3 0

3 years ago

Can y’all help find the surface area please and thank you

solong [7]

To find the area of a complex shape:

⇒ must cut the whole shape into a simpler shape

square with side lengths of 4 in
2 triangles with a base of 4 in. and a height of 8 in.
2 triangles with a base of 4 in. and a height of 10 in.

Let's calculate:

Area of 2 triangles with a base of 4 in. and a height of 8 in.

$Area = \frac{1}{2}*4*8 + \frac{1}{2}*4*8=16+16=32\\$

2 triangles with a base of 4 in. and a height of 10 in.

$Area = \frac{1}{2}*4*10 + \frac{1}{2}*4*10=20+20=40$

square with side lengths of 4 in

$Area = 4 * 4=16$

Total Area: 32 + 40 + 16 = 88 in²

Answer: 88 in²

Hope that helps!

8 0

2 years ago

Can anyone help me with this?

Lana71 [14]

216 / 48 = 4.5 hours
return
216 / 54 = 4 hours

total 4.5 + 4 = 8.5 hours

answer
B. 8.5 h

8 0

3 years ago

a squared paper shows the nets of cuboid A and cuboid B. do the two cuboids have the same surface area? plzzzzzzzzz answer

inn [45]

Answer:

No they don't.

Step-by-step explanation:

$A:\\(2*2*2)+(3*2*2)+(3*2*2)=\\(4*2)+(6*2)+(6*2)=\\8+12+12=\\20+12=\\32 cm^2\\\\B:\\(1*3*2)+(1*4*2)+(3*4*2)=\\(3*2)+(4*2)+(12*2)=\\6+8+24=\\14+24=\\38 cm^2$

5 0

3 years ago

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