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Serggg [28]
3 years ago
7

The number of people who use the ATM at night outside your local bank branch can be modeled as a Poisson distribution. On averag

e 1.2 customers arrive every hour (late at night). You park outside the bank to count the customers. What is the probability that in the hour between 10 and 11 PM at least one customer arrives?
Mathematics
1 answer:
Marina86 [1]3 years ago
6 0

Answer:

0.6988

Step-by-step explanation:

Given that the number of people who use the ATM at night outside your local bank branch can be modeled as a Poisson distribution.

Let X be the number of customers arriving between 10 and 11 am.

X is Poisson with mean= 1.2

Required probability

=  the probability that in the hour between 10 and 11 PM at least one customer arrives

= P(X≥1)

=1-P(X=0)

=1-0.3012

= 0.6988

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mars1129 [50]

Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}

Given:

\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25

Confidence level = 80%

t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397

*Use a <em>t</em>-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

3 0
2 years ago
What is the median of the following string of values?<br> 55, 18, 58, 49, 8, 77, 62, 26, 7.11
LuckyWell [14K]

Answer:

The answer is 49 if we are to assume you meant 7.11 and not 7,11.

If you meant 7,11 - the answer is 28.5.

Step-by-step explanation:

If we are assuming you meant "7,11" and not "7.11", then we would start by removing the lowest and highest numbers from the list respectively, and repeating the process until you only have 1 or 2 numbers left.

Here are the pairs of numbers removed if we are assuming you meant 7.11;

7.11 / 77

8 / 62

18 / 58

26 / 55

We are left with 49, and that would be your median.

However, if we were to assume you meant 7,11, then we'd have to start over and repeat the process.

7 / 77

8 / 62

11 / 58

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26 / 49 is our final answer; however we are not to assume this as we need a definite number. To resolve this, we would need to average the two numbers. To do this, we add them together and divide by how many numbers we added.

26 + 49 = 75.

75 / 2 = 28.5

Your median for this would be 28.5.

Hope this helps! Have a great rest of your day. :)

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Answer:

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