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2 years ago

10

65.874,326.59,13.555,7.959 round to the following numbers to 1 decimal place

2 answers:

expeople1 [14]2 years ago

8 0

Answer: 65.87

Step-by-step explanation: Identify which place value you are rounding to. The smaller the place value, the more accurate the final result will be.

Look to the next smallest place value, the digit to the right of the place value you're rounding to. For example, if you want to round to the nearest ten you'd look at the ones place.

Cloud [144]2 years ago

7 0

Answer:

a)65.9

b)326.6

c)13.6

d)8.0

Step-by-step explanation:

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Find the midpoint of the line segment whose endpoints are (-2, 5) and (4, -9).Find the midpoint of the line segment whose endpoi

jek_recluse [69]

Answer:

The midpoint is $(1,-2)$

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

$(x1,y1)=(-2,5)$

$(x2,y2)=(4,-9)$

substitute

$M(\frac{-2+4}{2},\frac{5-9}{2})$

$M(1,-2)$

8 0

2 years ago

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Phoenix [80]

Answer:

276

Step-by-step explanation:

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6 0

2 years ago

Make a comparison true. Drag and drop tenth value to fill in the blank. Select all that apply. 24. _ > 24. 34

spayn [35]

Answer:

Step-by-step explanation:

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3 0

1 year ago

If sinX= 0.9, what is the value of cos X?<br><br> Round the value to the nearest thousandth.

SSSSS [86.1K]

Answer: sqrt(19)/10

Step-by-step explanation:

sinx=0.9

x=arcsin(0.9)

Insert x for cos(x):

cos(arcsin(0.9)=

Use identify $cos(arcsin(x))=\sqrt{1-x^{2} }$ , so

$\sqrt{1-(\frac{9}{10})^{2}} =\sqrt{\frac{19}{100} } =\frac{\sqrt{19}}{10}$

Sorry if this is confusing.

6 0

3 years ago

Given that the diameter of Circle A is 6 cm , and the radius of Circle B is 18 cm , what can be concluded about the two circles?

ELEN [110]

Answer:

The radius of circle B is 6 times greater than the radius of circle A

The area of circle B is 36 times greater than the area of circle A

Step-by-step explanation:

we have

<em>Circle A</em>

$D=6\ cm$

The radius of circle A is

$r=6/2=3\ cm$ -----> the radius is half the diameter

<em>Circle B</em>

$r=18\ cm$

Compare the radius of both circles

$3\ cm< 18\ cm$

$18=6(3)$

The radius of circle B is six times greater than the radius of circle A

Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared

All circles are similar

In this problem the scale factor is 6

so

$6^{2}=36$

therefore

The area of circle B is 36 times greater than the area of circle A

8 0

2 years ago