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andriy [413]
3 years ago
8

Since Neil Armstrong was the first person to walk on the. moon, the contrapositive is

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0

Answer:

If nobody walked on the moon, then Neil Armstrong didn't

Step-by-step explanation:

The contrapositive flips the sign of "Neil Armstrong"  and the "moon," and also switches their position, so you will switch the hypothesis and conclusion as well

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Question is attached.<br>Step by step explanation needed!!​
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3 years ago
if p(x) = x2 – 1 and q(x)=5(x-1), which expression is equivalent to (p – q)(x)? a: 5(x – 1) – x2 – 1 b: (5x – 1) – (x2 – 1) c: (
zavuch27 [327]
P(x) = x^2 - 1
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3 years ago
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Rudiy27

Answer:

10 is the answer

Step-by-step explanation:

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6 0
3 years ago
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Find the sum of the first 17 terms of the arithmetic sequence 10, 14, 18, 22, 26...
kari74 [83]
10, 14, 18 ....

notice, we get the next term by simply adding 4 to the current term, thus "4" is the "common difference, and we know that 10 is the first term.

\bf n^{th}\textit{ term of an arithmetic sequence}&#10;\\\\&#10;a_n=a_1+(n-1)d\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;d=\textit{common difference}\\&#10;----------\\&#10;a_1=10\\&#10;d=4\\&#10;n=17&#10;\end{cases}&#10;\\\\\\&#10;a_{17}=10+(17-1)(4)\implies a_{17}=10+(16)(4)&#10;\\\\\\&#10;a_{17}=10+64\implies a_{17}=74\\\\&#10;-------------------------------

\bf \textit{ sum of a finite arithmetic sequence}&#10;\\\\&#10;S_n=\cfrac{n(a_1+a_n)}{2}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;----------\\&#10;a_1=10\\&#10;a_{17}=74\\&#10;n=17&#10;\end{cases}&#10;\\\\\\&#10;S_{17}=\cfrac{17(10+74)}{2}\implies S_{17}=\cfrac{17(84)}{2}\implies S_{17}=714
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3 years ago
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