Answer:
72 sq. mi
Step-by-step explanation:
Breaking this down, we have 2 right triangles with sides of 3, 4, and 5 miles, and 3 rectangles with dimensions 3 x 5, 4 x 5, and 5 x 5 miles. Remember that the area of a triangle is 1/2 x b x h , where b and h are the triangle's base and height. The base and height of the triangles at the bases of the figure are 3 and 4, so each triangle has an area of 1/2 x 3 x 4 = 1/2 x 12 = 6 sq. mi, or 6 + 6 = 12 sq. mi together.
Onto the rectangles, we can find their area by multiplying their length by their width. Since the width of these rectangles is the same for all three - 5 mi - we can make our lives a little easier and just "glue" the lengths together, giving us a longer rectangle with a length of 3 + 4 + 5 = 12 mi. Multiplying the two, we find the area of the rectangles to be 5 x 12 = 60 sq. mi.
Adding this area to the triangle's area gives us a total area of 12 + 60 = 72 sq. mi.
In analytic geometry, using the common convention that the horizontal axis represents a variable x and the vertical axis represents a variable y, a y-intercept or vertical intercept is a point where the graph of a function or relation intersects the y-axis of the coordinate system. As such, these points satisfy x = 0.
Answer:
$4000
Step-by-step explanation:
so $2800 was the starting price
100%-30%=70%
So 2800=70%
2800/7=400
400=10%
400*10=$4000
Answer:
42.06 ft²
Step-by-step explanation:
2 sides = 2(2.7 ft × 3.2 ft) = 2 × 8.64 ft² = 17.28 ft²
Front + back = 2(2.1 ft × 3.2 ft) = 2 × 6.72 ft² = 13.44 ft²
Top + bottom = 2(2.1 ft × 2.7 ft) = 2 × 5.67 ft² = <u>11.34 ft²
</u>
Total area = 42.06 ft²
Answer:
the first option
Step-by-step explanation:
variability !
what does that word tell us ?
it means that there are more individuals differences.
you could also use "accuracy" as the opposite - we are aiming for the mean value ...
imagine some bow and arrow tournament.
who wins ?
the person with the highest accuracy across all the attempts (and that means the lowest variability in the results across all attempts relatively to the target center representing the predefined mean value).
now look at the graphic for neighborhood A.
and then for neighborhood B.
which one has the data points more clustered around the center (where the mean value is going to be) ? this one has lower variability than the one where the data points are having more than one cluster or are even all over the place.
remember, for the variability you have to add all the differences to the mean value. the smaller the differences to the mean value, the smaller the variability.
in neighborhood B almost all data points have a larger difference to the mean value.
so, the variability will be higher here.
