Answer:
f = 
Step-by-step explanation:
Multiply both sides of the equation by 
f = -4/3 * 5/4
Simplify both sides of the equation.
f =
i hope this helps :)
Answer:
Each student club must contribute $ 33.33 in order to meet the fundraising goal.
Step-by-step explanation:
Given that a school fundraiser has a minimum target of $ 500. Faculty have donated $ 100 and there are 12 student clubs that are participating with different activities, to determine how much money should each club raise to meet the fundraising goal, the following calculation must be performed:
(500 - 100) / 12 = X
400/12 = X
33,333 = X
Thus, each student club must contribute $ 33.33 in order to meet the fundraising goal.
Answer:
237.9 meters
Step-by-step explanation:
Let x represent the length of the tunnel.
Applying the Cosine Law, we have:
x² = 201² + 146² - 2*201*146*Cos(85)
x² = 61,717 - 58,692*0.0872
x² = 61,717 - 5,117.9424
x² = 56,599.0576
x = √56,599.0576
x = 237.9 m (nearest tenth)
Step-by-step explanation:
1st year interest calculated = 3.25/100 × $4500/1 = $146.25
2nd year principal = 1st year principal + 1st year interest = $4500 + $146.25 = $4646.25. 2nd year interest calculated = 3.25/100 ×$4646.25/1 =$151
3rd year principal = 2nd principal + 2nd year interest = $4646.25 + $151 = $4797.25. 3rd year interest calculated = 3.25/100 × $4797.25/1 = $155.91
4th year principal = 3rd year principal + 3rd year interest =$4797.25 + $155.91 =$4953.16. 4th year principal calculated = 3.25/100 × 4953.16/1 =$160.98
5th year principal = 4th year principal + 4 year interest = &4953.16 +$160.98 = $5114.14. 5th year interest calculated = 3.25/100 × 5114.14/1 =$166.21
6th year principal =5th year principal + 5th year interest = $5114.14 + $166.21 =$5280.35. 6th year interest calculated = 3.25/100 × 5280.35/1 =$171.61
Amount = main principal + compound interest =$4500 +&146.25 +$151+$155.91+$160.98+$166.21+$171.61 =$5451.96
Answer:
y=6x-2
Step-by-step explanation:
6x-y-2-6x=0-6x
-y-2=-6x
-y-2+2=-6x+2
-y=-6x+2
-y/-1=-6x/-1+2/-1
y=6x-2
