The expression will look like this. (3*6)+4
Answer:
B. Yes, there are at least 10 people with weak bones and 10 people with strong bones in each group.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, a large sample size can be approximated to a normal distribution with mean and standard deviation 
The correct answer is:
B. Yes, there are at least 10 people with weak bones and 10 people with strong bones in each group.
Answer:
Option E is correct.
- Treatments: how the peppermint oil is dispersed
- Experimental unit: mice
- Response variable: number of mice in the dwellings
Step-by-step explanation:
The treatments in this type of statistical experiment refers to the part of the experiment that is tweaked, controlled or varied in the cases being studied. In this experiment, the method of essential oil dispersal is what is varied in the two experimental cases of this study.
Experimental Unit refers to the subject matters, who are participants in the experiment. They are the ones that the effect of the treatments is tested upon.
For this study, the experimental units are the mice subjected to either of the two methods of peppermint oil dispersal.
The response variable is how the experimental units (participants) respond to the treatments (experimental tweaks). Or how the tweaks manifest observable results in the participants of the study. For this study, the effect of the tweaks in the mice is shown in the number of mice that remain in each dwelling (where the two methods of peppermint oil dispersal have been implemented). Hence, the response variable is the number of mice in each dwelling.
Hope this Helps!!!
Answer:
line 2?
Step-by-step explanation:
Answer:
BC + CD = BD
Step-by-step explanation:
The segment addition postulate tells you that when a segment is divided into two parts, the sum of the lengths of the first part of the divided segment and the second part of the divided segment will be equal to the length of the whole segment.
If point C divides segment BD into BC and CD, then the sum of those two segments will match the whole.
