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myrzilka [38]
4 years ago
13

What happens when light strikes a dark heavy object

Chemistry
1 answer:
Natasha_Volkova [10]4 years ago
8 0
The colour of a substance determines the way it reacts when light rays are incident on it. When light rays strike a dark object, the dark object will absorb all the wavelengths of the light and convert them to heat energy, thereby increasing its temperature. Lighter colors do not absorb all the wavelengths of light, they reflected some depending on the type of color.
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Can the crabs see the plankton they eat near the ocean floor?
cricket20 [7]

Answer:

Explanation:

The crabs cannot see the plankton they eat near the ocean floor. For the crabs to see the plankton, some color of visible light would need to reach the plankton so that it can be reflected into the crabs' eyes.

4 0
3 years ago
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Estimate the solubility of CaCO3
Fudgin [204]

Answer:

CaCO3(s) <==> Ca2+(aq) + CO3 2-(aq)

Let X = the amount of CaCO3 dissolved in Na2CO3 or the amount of each ions formed i.e. Ca2+ and CO3 2–. Then, put this into the formula :

Ksp = [Ca2+] [CO3 2-]

5 × 10^-9 = [X]*[X]

X^2 = 5 × 10^-9

X = √5 × 10^-9

X = 7.07 x 10^-5 mole/L

So, the amount of CaCO3 dissolved in 0.1M Na2CO3 or the amount of Ca2+ and CO3 2- ions produced is 7.07 x 10^-5 mole/L

4 0
3 years ago
The amount of I−3(aq) in a solution can be determined by titration with a solution containing a known concentration of S2O2−3(aq
Pavlova-9 [17]

Answer : The molarity of I_3^- in the solution is, 0.128 M

Explanation :

The given balanced chemical reaction is,

2S_2O_2^{-3}(aq)+I_3(aq)\rightarrow S_4O_2^{-6}(aq)+3I^-(aq)

First we have to calculate the moles of Na_2S_2O_3.

\text{Moles of }Na_2S_2O_3=\text{Molarity of }Na_2S_2O_3\times \text{Volume of solution}

\text{Moles of }Na_2S_2O_3=0.260mole/L\times 0.0296L=0.007696mole

Conversion used : (1 L = 1000 ml)

Now we have to calculate the moles of I_3^-.

From the balanced chemical reaction, we conclude that

As, 2 moles of S_2O_2^{-3} react with 1 mole of I_3^-

So, 0.007696 moles of S_2O_2^{-3} react with \frac{0.007696}{2}=0.003848 mole of I_3^-

The moles of I_3^- = 0.003848 mole

Now we have to calculate the molarity of I_3^-.

\text{Molarity of }I_3^-=\frac{\text{Moles of }I_3^-}{\text{Volume of solution}}

Now put all the given values in this formula, we get:

\text{Molarity of }I_3^-=\frac{0.003848mole}{0.03L}=0.128mole/L=0.128M

Therefore, the molarity of I_3^- in the solution is, 0.128 M

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Answer:

anna ou

Explanation:

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