<span> </span><span>Fusion
reaction is a type of nuclear reaction where two or more nuclei combine or
collide to form an element with a higher atomic number. This happens when the
collision is in a very high speed. In this process, some of the matter of the
fusing nuclei is converted to energy.</span>
Answer:
Hydrogen has the highest rate of effusion
First you need to know how many moles you would get from 165 g of carbon dioxide.
Carbon = 12
Oxygen 2 = 16 x 2 = 32
Total: 32 + 12 = 44
- Use proportions
1 mol CO2 x 1 mol CO2 44 g
---------------- = ---------- or ----------------- = ----------
44 g 165 x 165 g
165/44 = 3.75 moles CO2
- Last step is to multiply the amount of moles by Avagadros number, 6.02 x 10^23
3.75 x 6.02 x 10^23 = 2.25 x 10^24 molecules
- Keep in mind if your answer can be a little different than mind if you either round or keep the same numbers. I hope this Really Helps ! c:
Answer : The rate constant at 525 K is, 
Explanation :
According to the Arrhenius equation,
or,
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= rate constant at 
= 
= rate constant at 
= ?
= activation energy for the reaction = 
R = gas constant = 8.314 J/mole.K
= initial temperature = 701 K
= final temperature = 525 K
Now put all the given values in this formula, we get:
![\log (\frac{K_2}{2.57M^{-1}s^{-1}})=\frac{1.5\times 10^5J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{701K}-\frac{1}{525K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7B2.57M%5E%7B-1%7Ds%5E%7B-1%7D%7D%29%3D%5Cfrac%7B1.5%5Ctimes%2010%5E5J%2Fmol%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B701K%7D-%5Cfrac%7B1%7D%7B525K%7D%5D)
Therefore, the rate constant at 525 K is,
From the formula of methane it is clear that one mole of methane has 4hydrogen atoms. So, 37.6×1023 hydrogen atoms are there in 25.0 g of methane. Therefore, 9.4×1023methane molecules and 9.4×1023 hydrogen and 37.6×1023carbon atoms are there in 25.0 g of methane.
mark me brainliestt :))
