Answer:
W1 = W2 = 50k Joules (assuming W1 and W2 have the same force constant, k)
W1 - W2 = 0
Step-by-step explanation:
Work done in stretching a spring is given by 1/2ke^2
Where, k is force constant and e is extension
e1 = 30cm - 20cm = 10cm
W1 = 1/2k(e1)^2 = 1/2×k×10^2 = 50k Joules
e2 = 40cm - 30cm = 10cm
W2 = 1/2k(e2)^2 = 1/2×k×10^2 = 50k Joules
W1 = W2 = 50k Joules provided W1 and W2 have equal force constant
Therefore, W1 - W2 = 0
Answer:
Step-by-step explanation:
CD is Pole
∠CAD = 4° {Alternate interior angles}
ΔCAD,
In ΔCDB,
∠B = 5° {Alternate interior angles}
Answer:
y=-2x-1
Step-by-step explanation:
Answer:-5
-8x-2=-16
-16+11=-5
12 x 6 x 3 = 216
Volume = 216 cm cubed
216/0.03 = 7200
Answer = 7200 pencils
Hope it helped :)
