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Dmitry [639]
2 years ago
13

Of 30 student, 1/3 play sports. Of those who play sports, 2/5 play soccer. How many students play soccer.

Mathematics
1 answer:
Katena32 [7]2 years ago
5 0

Answer:

12

Step-by-step explanation:

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Select all the correct answers.
fenix001 [56]

The function g(x) is created by applying an <em>horizontal</em> translation 4 units left and a reflection over the x-axis. (Correct choices: Third option, fifth option)

<h3>How to determine the characteristics of rigid transformations by comparing two functions</h3>

In this problem we have two functions related to each other because of the existence of <em>rigid</em> transformations. <em>Rigid</em> transformations are transformations applied to <em>geometric</em> loci such that <em>Euclidean</em> distance is conserved at every point of the <em>geometric</em> locus.

Let be f(x) = - 2 · cos (x - 1) + 3, then we use the concept of <em>horizontal</em> translation 4 units in the + x direction:

f'(x) = - 2 · cos (x - 1 + 4) + 3

f'(x) = - 2 · cos (x + 3) + 3     (1)

Now we apply a reflection over the x-axis:

g(x) = - [- 2 · cos (x + 3) + 3]

g(x) = 2 · cos (x + 3) - 3

Therefore, the function g(x) is created by applying an <em>horizontal</em> translation 4 units left and a reflection over the x-axis. (Correct choices: Third option, fifth option)

To learn more on rigid transformations: brainly.com/question/1761538

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4 0
1 year ago
A. dashed line, shade below
Ronch [10]

Answer:

the answer is A

Step-by-step explanation:

3 0
3 years ago
HELPPPPPPPPPPPPPPPPPPP!!!
Angelina_Jolie [31]

Answer:

15.13cm

Step-by-step explanation:

From that above question:

We are told that:

Lateral surface area of a right circular cone : πr√r² + h²

We are give the following parameters:

Lateral surface area = 236.64cm²

Radius = 4.75cm

We are to find the height

Making h the subject of the formula

h = √[(A/r)² - πr²]/π

h = √[(236.64/4.75)²- π ×4.75²]/π

h = 15.12975 cm

Approximately to the nearest hundredth = 15.13cm

7 0
2 years ago
Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
USPshnik [31]

First, expand the terms inside the bracket you will get

(( \tan {}^{2} (x)  + 2 \tan(x)  \sin(x)  +  \sin {}^{2} (x)  - ( \tan {}^{2} (x)  - 2 \tan(x)  +  \sin {}^{2} (x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x)  \sin {}^{2} (x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

5 0
2 years ago
1.What is the simplified form of the following expression?
kipiarov [429]
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6 0
2 years ago
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