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svlad2 [7]
3 years ago
13

In the SI system of units, the mole is one of seven base units. It is frequently used in chemical calculations. However, a mole

of something is just a particular quantity of it. It is not a unit of measure in the way that meters, seconds, and kilograms are. Calculations performed with the number of moles of a substance could also be performed with the number of particles of a substance. Based on this information, do you think that the mole should be considered a base unit in the SI system? Explain why or why not.
Chemistry
2 answers:
Debora [2.8K]3 years ago
5 0

We have to discuss here whether mole should be considered as a base unit in SI system or not.

The answer is-   mole is considered as base unit in SI system.

There are seven base units in the SI system. They are- kilogram (kg) for mass, second (s) for time, kelvin (K) for temperature, ampere (A) for electric current, mole (mol) for the amount of substance, candela (cd) for luminous intensity and meter (m) is for distance.

Mole is defined as the amount of substance that contains as many elementary entities as there are atoms in 0.012 kilogram of carbon-12. One mole contains exactly 6.022 X 10²³ elementary entities.

This number  6.022 X 10²³ is the fixed numerical value which is called Avogadro number which is universally accepted number. Hence mole is also base unit in the SI system.


ad-work [718]3 years ago
3 0

Answer

This number  6.022 X 10²³ is the fixed numerical value which is called Avogadro number which is universally accepted number. Hence mole is also base unit in the SI system.

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3 0
3 years ago
calculate the molality of commercial HCl solution which is 12.1Molarity, and has a density of 1.19g/mL, and is 37.2wt.%HCl.
shutvik [7]

Answer:

0.44165 Molal

8 0
3 years ago
Write a complete, balanced chemical equation where tin metal reacts with aqueous hydrochloric acid to produce tin(II) chloride a
AleksAgata [21]

Answer:

1. The balanced equation is given below:

Sn (s) + 2HCl (aq) –> SnCl₂ (aq) + H₂ (g)

2a. H is oxidized.

2b. Sn is reduced.

Explanation:

1. Balanced equation for the reaction between tin (Sn) metal and aqueous hydrochloric acid (HCl) to produce tin(II) chloride (SnCl₂) and hydrogen gas (H₂).

This is illustrated below:

Sn (s) + HCl (aq) –> SnCl₂ (aq) + H₂ (g)

There are 2 atoms of Cl on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:

Sn (s) + 2HCl (aq) –> SnCl₂ (aq) + H₂ (g)

Now, the equation is balanced

2. Determination of the element that is oxidize and reduced.

This can be obtained as follow:

We shall determine the change in oxidation number of each element.

NOTE:

a. The oxidation number of H is always +1 except in hydrides where it is –1.

b. The oxidation state of Cl is always –1.

Sn (s) + 2HCl (aq) –> SnCl₂ (aq) + H₂ (g)

For Tin (Sn):

Sn = 0

SnCl₂ = 0

Sn + 2Cl = 0

Cl = – 1

Sn + 2(–1) = 0

Sn – 2 = 0

Collect like terms

Sn = 0 + 2

Sn = +2

Therefore, the oxidation number of Tin (Sn) changes from 0 to +2

For H:

H = +1

H₂ = 0

The oxidation number of H changes from +1 to 0

For Cl:

Cl is always –1. Therefore no change.

Summary:

Element >>Change in oxidation number

Sn >>>>>>>From 0 to +2

H >>>>>>>>From +1 to 0

Cl >>>>>>>No change

Therefore,

Sn is reduced since its oxidation number increased from 0 to +2.

H is oxidized since it oxidation number reduced from +1 to 0

4 0
3 years ago
Al(OH)3 + 3 HCl = AlCl3 + 3 H2O
Kryger [21]

Answer:

1) 1.235 g.

2) 0.61 g.

Explanation:

  • From the balanced equation:

<em>Al(OH)₃ + 3HCl → AlCl₃ + 3H₂O.</em>

1.0 mol of Al(OH)₃ reacts with 3.0 moles of HCl to produce 1.0 mol of AlCl₃ and 3.0 moles of H₂O.

<em>1) How many grams of HCl can a tablet with 0.880 g of Al(OH)₃ consume? </em>

  • To calculate the amount of HCl needed to consume 0.880 g of Al(OH)₃, we need to calculate the no. of moles of Al(OH)₃:

no. of moles of Al(OH)₃ = mass/molar mass = (0.880 g)/(78.0 g/mol) = 1.13 x 10⁻² mol.

∵ Every 1.0 mol of Al(OH)₃ needs 3.0 moles of HCl to be consumed.

∴ 1.13 x 10⁻² mol of Al(OH)₃ needs (3 x 1.13 x 10⁻² = 3.385 x 10⁻² mol) of HCl.

The no. of grams of HCl = no. of moles of HCl x molar mass of HCl = (3.385 x 10⁻² mol)(36.5 g/mol) = 1.235 g.

<em>2) How much H₂O?</em>

∵ Every 1.0 mol of Al(OH)₃ produces 3.0 moles of H₂O.

∴ 1.13 x 10⁻² mol of Al(OH)₃ produces (3 x 1.13 x 10⁻² = 3.385 x 10⁻² mol) of H₂O.

<em>The no. of grams of H₂O = no. of moles of H₂O x molar mass of H₂O </em>= (3.385 x 10⁻² mol)(18.0 g/mol) = <em>0.6092 g ≅ 0.61 g.</em>

7 0
3 years ago
For the reaction 2HNO3 + Mg(OH)2 → Mg(NO3) 2 + 2H2O, how many grams of magnesium nitrate are produced from 4 grams of nitric aci
kotegsom [21]

Answer:

First check to make sure you have a balanced equation

Second use mole ratios to set up what you need to know

Finally convert the moles to grams using the correct molecular weight

I will get you started

According to the reaction above, one mole of Magnesium Nitrate is produced from 2 moles of Nitric Acid

1 mole of Mg(NO3)2/2 moles of HNO3

5 grams of Nitric acid contains

5 g * 1 mole/63 g of Nitric Acid = 0.079365079 moles

Explanation:

8 0
3 years ago
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