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LekaFEV [45]
3 years ago
15

Based on what basis the elements had been arranged

Chemistry
1 answer:
salantis [7]3 years ago
6 0

Answer:

B

The increase in the atomic number

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A ____________ is a physical combination of things that can be separated. mixture compound
Degger [83]

Answer:

mixture

Explanation:

A mixture is something that can be separated, while a compound is something that can be separated (unless by chemicals).

An example of a mixture would be trail mix. You can separate the components without using chemicals.

~theLocoCoco

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3 years ago
based on the cause and effect relationship between the magnets, which phenomenon is the teacher modeling for her students.
faltersainse [42]

Answer:

Someone breaking up.

Explanation:

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2 years ago
What is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°C to 70.0°C when 2,520 J of hea
Ksju [112]

Answer:

A. 0.00420 J/(gi°C)

Explanation:

i got it rigt

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2 years ago
Aaliya knows that sliced apples turn brown when left out in the open air. She also knows that pouring certain liquids on then wi
fenix001 [56]

An apple should be cut into 4 equal pieces, then put each slice in a separate container and label accordingly with letters A, B, C, and Control. Put water, ginger ale, and lemon juice into containers A, B, and C respectively but leave the Control untouched. Observe which of the slices in containers A, B, C will stay the same color after the one in control turns brown, if the slice maintains its color then the liquid added prevents an apple slice from browning. The variables are the liquids added and the control is the slice that did not have anything added to it.


7 0
3 years ago
A frictionless piston cylinder device is subjected to 1.013 bar external pressure. The piston mass is 200 kg, it has an area of
Bad White [126]

Answer:

a) T_{2} = 360.955\,K, P_{2} = 138569.171\,Pa\,(1.386\,bar), b) T_{2} =  347.348\,K, V_{2} = 0.14\,m^{3}

Explanation:

a) The ideal gas is experimenting an isocoric process and the following relationship is used:

\frac{T_{1}}{P_{1}} = \frac{T_{2}}{P_{2}}

Final temperature is cleared from this expression:

Q = n\cdot \bar c_{v}\cdot (T_{2}-T_{1})

T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{v}}

The number of moles of the ideal gas is:

n = \frac{P_{1}\cdot V_{1}}{R_{u}\cdot T_{1}}

n = \frac{\left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}} \right)\cdot (0.12\,m^{3})}{(8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K} )\cdot (298\,K)}

n = 5.541\,mol

The final temperature is:

T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (30.1\,\frac{J}{mol\cdot K} )}

T_{2} = 360.955\,K

The final pressure is:

P_{2} = \frac{T_{2}}{T_{1}}\cdot P_{1}

P_{2} = \frac{360.955\,K}{298\,K}\cdot \left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}}\right)

P_{2} = 138569.171\,Pa\,(1.386\,bar)

b) The ideal gas is experimenting an isobaric process and the following relationship is used:

\frac{T_{1}}{V_{1}} = \frac{T_{2}}{V_{2}}

Final temperature is cleared from this expression:

Q = n\cdot \bar c_{p}\cdot (T_{2}-T_{1})

T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{p}}

T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (38.4\,\frac{J}{mol\cdot K} )}

T_{2} =  347.348\,K

The final volume is:

V_{2} = \frac{T_{2}}{T_{1}}\cdot V_{1}

V_{2} = \frac{347.348\,K}{298\,K}\cdot (0.12\,m^{3})

V_{2} = 0.14\,m^{3}

4 0
3 years ago
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