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kaheart [24]
3 years ago
11

In a chess match, a win counts as 1 point, a draw counts as ½ point, and a loss counts as 0 points. After 15 games, the winner w

as 4 points ahead of the loser. How many points did the loser have?
Mathematics
1 answer:
Tanzania [10]3 years ago
8 0

Answer:

The loser had 5.5 points

The he winner had 9.5  points

Step-by-step explanation:

9.5 - 5.5 = 4

5.5 + 9.5 = 15

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What division sentence means the same as the following subtract sentences?
Kaylis [27]
12 can be divisible by 8,4
8 0
3 years ago
If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t-16t^2.

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}

(\text{Average velocity})_{0.1\ s}=696\ ft/s

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}

(\text{Average velocity})_{0.01\ s}=7536\ ft/s

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}  

(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}

(\text{Average velocity})_{0.001\ s}=75936\ ft/s

5 0
4 years ago
A square field has a perimeter if 3.6km what is the length of one side in metres​
spayn [35]

Answer:

A square field has a perimeter if 3.6km what is the length of one side in metres

Step-by-step explanation:

A square field has a perimeter if 3.6km what is the length of one side in metres

4 0
3 years ago
Read 2 more answers
If C(5,-5) and D(7,3), then what is the length of CD?​
Aleks04 [339]

Answer:

≈ 6.16

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = C(5, - 5) and (x₂, y₂ ) = D(7, 3)

d = √ (7 - 5)² + (3 + 5)²

  = √ 2² + 8² = √ 4 + 64 = √68 ≈ 6.16 ( to 2 dec. places )

8 0
4 years ago
Read 2 more answers
Find the volume of a pyramid with a square base, where the perimeter of the base is
Yuki888 [10]

Answer:

V= 57.8 cm^3

Step-by-step explanation:

i had the same question and got it wrong and it showed me the correct answer so basically

V=1/3(11.56(15)

V=57.8

3 0
3 years ago
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