Which pairs of polygons are congruent?
2 answers:
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Answer:
y = - 3x + 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange 2y = 14 + x into this form
Divide all terms by 2
y = 7 + x ← in slope- intercept form
with slope m =
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= - 3, hence
y = - 3x + c ← is the partial equation of the perpendicular line
To find c substitute (- 2, 8) into the partial equation
8 = 6 + c ⇒ c = 8 - 6 = 2
y = - 3x + 2 ← equation of perpendicular line
Answer:
B=23.19
Step-by-step explanation:
First, find the last side of the triangle using the Pythagorean theorem.
Then, find the missing angle, lets name it B.
The angle B can be found using the inverse sine function.
B=arcsin(opp/hyp)
let's recall that the graph of a function passes the "vertical line test", however, that's not guarantee that its inverse will also be a function.
A function that has an inverse expression that is also a function, must be a one-to-one function, and thus it must not only pass the vertical line test, but also the horizontal line test.
Check the picture below, the left-side shows the function looping through up and down, it passes the vertical line test, in green, but it doesn't pass the horizontal line test.
now, check the picture on the right-side, if we just restrict its domain to be squeezed to only between [0 , π], it passes the horizontal line test, and thus with that constraint in place, it's a one-to-one function and thus its inverse is also a function, with that constraint in place, or namely with that constraint, cos(x) and cos⁻¹(x) are both functions.
