Answer:
1/7
Step-by-step explanation:
If one child was born on a Monday, then we don't have to consider that when solving the question, as it asks if both children were born on a Monday.
Thus, we only need to find the probability that the second child is born on a Monday. Since there are 7 days in a week and equally likely that the child is born on any day, then the probability of the child being born on a Monday would be 1/7.
Answer:
x^2 - 5x = 14
x^2 - 5x-14 = 0
Now, we have to find the multiples of -14 and numbers that add/subtract to -5; this helps to find the factors.
-7+2 = -5
-7*2 = -14
Based on the above info, we can find out my factors; they are:-
(x-7)(x+2)
6x+3y=15
6*2+3y=15
12+3y=15
3y=3
y=1
6x+3y=15
6*5+3y=15
30+3y=15
3y=-15
y=-5
The answers is y=1 & -5
Because ΔQRS is congruent to <span>ΔTUV, the the segments GS and TV are also congruent due to the letter order (Q and T are first and S and V are 3rd.) Since they are congruent QS=TV. So 3v + 2 = 7v - 6
</span><span>
</span><span>Work:
</span>3v + 2 = 7v - 6
+6 +6
3v + 8=7v
-3v -3v
<u>8</u> = <span><u>4v</u>
</span>4 4
2 = v
3(2) + 2 = GS
6+2 = GS
8 = GS
7(2) - 6 = TV
14-6=TV
8 = TV
Final Answer: 8=QS and 8=TV
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