Answer:
saturn
Step-by-step explanation:
it goes Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune
The coordinates of a point is the location of the point in a plane.
<em>The coordinates of the centers of holes are: (48.5, 28) and (28, 48.5)</em>
Given
![\theta_1 = \theta_2 = \theta_3 = 30^o](https://tex.z-dn.net/?f=%5Ctheta_1%20%3D%20%5Ctheta_2%20%3D%20%5Ctheta_3%20%3D%2030%5Eo)
![R = 60](https://tex.z-dn.net/?f=R%20%3D%2060)
![r = 56](https://tex.z-dn.net/?f=r%20%3D%2056)
I've added an attachment as an illustration
<u />
<u>Considering </u>
<u />
To solve for x1, we make use of cosine ratio.
So, we have:
![\cos(\theta_1) =\frac{x}{r}](https://tex.z-dn.net/?f=%5Ccos%28%5Ctheta_1%29%20%3D%5Cfrac%7Bx%7D%7Br%7D)
Make x the subject
![x_1 = r \times \cos(\theta_1)](https://tex.z-dn.net/?f=x_1%20%3D%20r%20%5Ctimes%20%5Ccos%28%5Ctheta_1%29)
![x_1 = 56 \times \cos(30^o)](https://tex.z-dn.net/?f=x_1%20%3D%2056%20%5Ctimes%20%5Ccos%2830%5Eo%29)
![x_1 = 48.5](https://tex.z-dn.net/?f=x_1%20%3D%2048.5)
To solve for y1, we make use of sine ratio.
So, we have:
![\sin(\theta_1) =\frac{y_1}{r}](https://tex.z-dn.net/?f=%5Csin%28%5Ctheta_1%29%20%3D%5Cfrac%7By_1%7D%7Br%7D)
Make y the subject
![y_1 = r \times \sin(\theta_1)](https://tex.z-dn.net/?f=y_1%20%3D%20r%20%5Ctimes%20%5Csin%28%5Ctheta_1%29)
![y_1 = 56 \times \sin(30^o)](https://tex.z-dn.net/?f=y_1%20%3D%2056%20%5Ctimes%20%5Csin%2830%5Eo%29)
![y_1 = 28](https://tex.z-dn.net/?f=y_1%20%3D%2028)
So, we have:
![(x_1,y_1) = (48.5,28)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%20%3D%20%2848.5%2C28%29)
<u>Considering </u>
<u />
To solve for x2, we make use of cosine ratio.
So, we have:
![\cos(\theta_1+\theta_2) =\frac{x_2}{r}](https://tex.z-dn.net/?f=%5Ccos%28%5Ctheta_1%2B%5Ctheta_2%29%20%3D%5Cfrac%7Bx_2%7D%7Br%7D)
Make x the subject
![x_2 = r \times \cos(\theta_1+\theta_2)](https://tex.z-dn.net/?f=x_2%20%3D%20r%20%5Ctimes%20%5Ccos%28%5Ctheta_1%2B%5Ctheta_2%29)
![x_2 = 56 \times \cos(30+30)](https://tex.z-dn.net/?f=x_2%20%3D%2056%20%5Ctimes%20%5Ccos%2830%2B30%29)
![x_2 = 56 \times \cos(60^o)](https://tex.z-dn.net/?f=x_2%20%3D%2056%20%5Ctimes%20%5Ccos%2860%5Eo%29)
![x_2 = 28](https://tex.z-dn.net/?f=x_2%20%3D%2028)
To solve for y1, we make use of sine ratio.
So, we have:
![\sin(\theta_1+\theta_2) =\frac{y_2}{r}](https://tex.z-dn.net/?f=%5Csin%28%5Ctheta_1%2B%5Ctheta_2%29%20%3D%5Cfrac%7By_2%7D%7Br%7D)
Make y the subject
![y_2 = r \times \sin(\theta_1+\theta_2)](https://tex.z-dn.net/?f=y_2%20%3D%20r%20%5Ctimes%20%5Csin%28%5Ctheta_1%2B%5Ctheta_2%29)
![y_2 = 56 \times \sin(30+30)](https://tex.z-dn.net/?f=y_2%20%3D%2056%20%5Ctimes%20%5Csin%2830%2B30%29)
![y_2 = 56 \times \sin(60)](https://tex.z-dn.net/?f=y_2%20%3D%2056%20%5Ctimes%20%5Csin%2860%29)
![y_2 = 48.5](https://tex.z-dn.net/?f=y_2%20%3D%2048.5)
So, we have:
![(x_2,y_2) = (28,48.5)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29%20%3D%20%2828%2C48.5%29)
<em>Hence, the coordinates of the centers of the holes are: (48.5, 28) and (28, 48.5)</em>
Read more about coordinate geometry at:
brainly.com/question/8121530
The answer to this question would be: C.5x = 5
In this question, you got two equation which was:<span>1st: 2x + y = 3
2nd: x - 2y = -1</span>
You are asked to multiply one of the equation and add it. If you multiply the first equation, the number of y would be same so the y variable will be removed. If you multiply the second equation, the number of x would be same so the x variable will be removed.
In the answer, all variable that used is x, so the one you need to multiply should be the first equation(removing y with result with x)
<span>4x + 2y = 6
x - 2y = -1
__________+
5x +0y = 5
</span>
Alonzo has $100 in his account.