Answer:
Step-by-step explanation:
From table 1,
f(x) = bˣ
For x = -1,
f(-1) = 0.5
0.5 = (b)⁻¹
b =
b = 2
For x = 1.585,
f(1.585) = 3
3 = 
3 = 


For x = 2.585,
f(2.585) = 
= 
= 4 × 1.5 [Since,
]
= 6
From table 2,
g(x) = 
For x = 0.5,
g(0.5) = -1
-1 = 
b⁻¹ = 0.5
b = 2
For x = 2,
g(2) = 1
1 = 
For x = 6,
g(6) = 2.585
2.585 = 
2.585 = 
2.585 = 
2.858 - 1 = 

For x = 3,
g(3) = 
g(3) = 1.585
Answer:

Step-by-step explanation:


Add:- 
and 
So, 
Add 7 to both sides:-

Divide both sides by 11:-


<u>OAmalOHopeO</u>
Answer:
x = 8.0
Step-by-step explanation:
sin theta = opposite/ hypotenuse
sin 53 = x/10
Multiply by 10 on each side
10 sin 53= x
7.9863551 =x
Rounding to the nearest tenth
8.0 =x
2.25 x 1000 = 2250.
That's how much yds of ribbons he needs.