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Umnica [9.8K]
4 years ago
9

Consider the vitamin capsule below.

Mathematics
1 answer:
shusha [124]4 years ago
7 0

Answer:

We have a cylinder and two semispheres.

The volume of a cylinder is equal to:

Vc =h*pi*r^2

where h is the height, r is the radius, and pi = 3.14

We know that the diameter is d = 8.4 mm, and the radius is half of that:

r = 8.4mm/2 = 4.2mm

Then the volume of the cylinder is:

Vc = 15.2mm*3.14*(4.2mm)^2 = 841.9 mm^3

The volume of a sphere is:

Vs = (3/4)*pi*r^3

The radius of the sphere is the same as the radius of the cylinder, and for a semisphere, we have half of the volume written above,

Vss = (3/8)*3.14*(4.2mm)^2 = 87.2mm^3

and we have two of those, so the total volume is:

Vt = 841.9 mm^3 + 2*87.2mm^3 = 1016.3 mm^3

The surface area of the figure is equal to the curved surface of the cylinder plus the surface of the two semispheres.

The curved surface of the cylinder is:

Sc = 2*pi*r*h = 2*3.14*4.2mm*15.2mm  = 400.9 mm^2

The surface of a sphere is:

Ss = 4*pi*r^2

and for each semisphere, we can find the surface by dividing the previous equation by two, but we have two semispheres, so we can jump a step and think the two semispheres as only one sphere.

Ss = 4*3.14*(4.2mm)^2 = 221.6mm^2

The total surface is St = 221.6mm^2 + 400.9 mm^2 = 622.5 mm^2

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The equation C = 20n + 35 represents the relationship between the cost of school volleyball uniforms, C, in dollars, and the num
Margaret [11]

The equation represent a linear relation with the y-intercept

representing the amount of initial fee.

Correct response:

1. 28 volleyball uniforms

2. Price per uniform

3. Initial flat order fee

4. 10 fewer volleyball uniform

<h3>Methods used for finding the above values</h3>

The given equation that represents the relationship between the cost of school volleyball uniform is; C = 20·n + 35

Where;

C = The uniform costs

n = The number of volleyball uniform ordered

The maximum amount the school has to spend = $600

1. The number of uniforms the school can buy is given by setting C = 600 as follows;

  • C = 20·n + 35

Therefore;

600 = 20·n + 35

20·n = 600 - 35 = 565

n = \dfrac{565}{20} = \mathbf{28.25}

Rounding down to the nearest whole number, we have;

  • The number of uniforms the school can buy, n = <u>28 volleyball uniforms</u>.

2. The number 20 represent the additional cost for each extra uniform, which is the unit cost therefore;

  • 20 represents a <u>$20 price per uniform</u>.

3. The 35 in the equation represents an initial <u>flat fee</u>, such as an

ordering or initial fee, which is fixed.

Therefore;

  • The number 35 represent the <u>fixed cost </u>for producing the uniforms

4. The price per uniform of $30 changes the coefficient of <em>n</em> from 20 to 30 as follows;

C = 30·n + 35

The number of uniforms the school can by with $600 is therefore;

n = \dfrac{600 - 35}{30} = \mathbf{18.8 \overline 3}

Which gives;

The number of uniforms the school can purchase at $30 per uniform is n = 18 volleyball uniforms

The difference in the number of uniforms purchased = 28 - 18 = 10

Therefore;

  • The school can purchase <u>10 fewer uniforms</u> at $30 per uniform

Learn more about linear equations here:

brainly.com/question/10452752

4 0
2 years ago
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