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3 years ago

6. Find the possible values of n in the inequality –3n < 81. A. n > –27 B. n < 27 C. n = –27 D. n = 27

1 answer:

6 0

-3n < 81...divide both sides by -3, change the inequality sign
n > -81/3
n > - 27 <==

** in an inequality, when dividing/multiplying by a negative number, the inequality sign changes

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7TH GRADE MATH! PLEASE HELP BRAINLIEST ANSWER!

Harlamova29_29 [7]

If y varies directly with x, the formula of the equation is y=ax, where a is a constant.
y=ax
(21)=a(7)
a=3
y=ax
y=(3)(-1.66)
y=-4.98, x=-1.66

If y varies inversely with x, the formula of the equation is y=a/x, where a is a constant
y=a/x
9=a/2.5
a=22.5
y=22.5/x
y=22.5/-0.6
y=-37.5

I hope this helped! =)
I hope you didn't mind but I got this from a website called: answers.yahoo.com but I got your answer.

3 0

3 years ago

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What is an equation of the line that passes through the points : (−6,−5) and (−6,−2)?

Leno4ka [110]

Answer: x= -6

Step-by-step explanation:

It will be a vertical line parallel to the y-axis at -6 on the x-axis. It passes through every y-value, including the given -5 and -2

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3 years ago

Using a formula estimate the body surface area of a person whose height is 150 cm and who weighs 80 kg.

ladessa [460]

Answer:

B. $1.83\text{ m}^2$

Step-by-step explanation:

We are asked to find the body surface area of a person whose height is 150 cm and who weighs 80 kg.

$\text{Body surface area}( m^2)=\sqrt{\frac{\text{Height (cm)}\times \text{Weight (kg)}}{3600}}$

Substitute the values:

$\text{Body surface area}( m^2)=\sqrt{\frac{150\text{ cm}\times 80\text{(kg)}}{3600}}$

$\text{Body surface area}( m^2)=\sqrt{\frac{12,000}{3600}}$

$\text{Body surface area}( m^2)=\sqrt{3.3333333}$

$\text{Body surface area}( m^2)=1.825741$

$\text{Body surface area}( m^2)=1.83$

Therefore, the body surface area of the person would be 1.83 square meters.

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3 years ago

Find the range and the interquartile range for 28,29,33,28,27,32,30,27

AfilCa [17]

Answer:

33 - 27 = 6

Step-by-step explanation:

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2 years ago

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The floor of a rectangular deck has an area of 600 sq. ft. The floor is 20 ft. wide. How long is the floor?

grin007 [14]

The question is asking us to determine the length of the floor of a rectangular deck. The rectangular deck has an area of 600 squared feet. The floor is 20 feet wide ( W = 20 ft ). Formula for the area of the rectangle is: A = L x W. 600 = L X 20; L = 600 : 20; L = 30 ft. Answer: The floor is 30 ft long.

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2 years ago