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1 year ago

Please help me with this please and thank you

Mathematics

2 answers:

Damm [24]1 year ago

7 0

Answer:

A. 3, 6, 12, 24

Step-by-step explanation:

In A, you're multiplying by 2 each time.

Mekhanik [1.2K]1 year ago

4 0

Answer:

Step-by-step explanation:

it's a geometric sequence since it is continuously being multiplied by the same number which in this case is 2.

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alukav5142 [94]

Answer:

Opposite, You don't give the shapes so that's an assumption.

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3 years ago

Read 2 more answers

pls help meh.. Which of the following statements best describes the effect of replacing the graph of y = f(x) with the graph of

pantera1 [17]

Answer:

Step-by-step explanation:

4 0

3 years ago

hi! i was wondering if i could have some help and maybe someone do 2 and another do 2 idk but thank u sm

Margarita [4]

Answer:

1) 5 2) 7 3) 9 4) 8

Step-by-step explanation:

you add and subtract the numbers, for example, number 1, the total is 9 and it shows 4 so 5. Or 3, K to I is 3 and 11 (the total) minus 3 equals 8, plus the 1 so 9. Hope this helps! Have a good day! :)

8 0

2 years ago

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than

Sedbober [7]

Testing the hypothesis, it is found that:

The null hypothesis is: $H_0: \mu \leq 10$

The alternative hypothesis is: $H_1: \mu > 10$

The critical value is: $t_c = 1.74$

The decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of at most 10 pounds, that is:

$H_0: \mu \leq 10$

At the alternative hypothesis, it is tested if the mean loss is of more than 10 pounds, that is:

$H_1: \mu > 10$

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a significance level of 0.05 and 18 - 1 = 17 df.

Hence, using a calculator for the t-distribution, the critical value is: $t_c = 1.74$ .

Hence, the decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Item c:

We have the standard deviation for the sample, hence the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem, we have that:

$\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18$

Thus, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}$

$t = 1.41$

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0

2 years ago

Find the nth term, a n, of the given arithmetic sequence. a^1 = 75, d = –8, n = 11

kap26 [50]

An = a1+d*(n-1)
a11 = 75-8*(11-1) = -5

4 0

3 years ago