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Westkost [7]
4 years ago
5

How many moles of argon are present if there are 1.23 x 10^20 atoms?

Chemistry
1 answer:
suter [353]4 years ago
4 0

Answer:

2.04×10⁻⁴ moles of Ar

Explanation:

We begin from this knowledge:

1 mol of substance has 6.02×10²³ particles

Let's solve this by a rule of three:

6.02×10²³ atoms are contained in 1 mol of Ar

1.23×10²⁰ atoms must be contained in (1.23×10²⁰ . 1) / 6.02×10²³ =

2.04×10⁻⁴ moles of Ar

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The correct answer for the addition of 5.8 g + 2.26g + 1.311g + 2 g is?
jeka94

Answer:

= 11.371g

Explanation:

Hope This Helps! :]

4 0
3 years ago
Help please please please please
Rom4ik [11]

Answer:

D. 18.7 grams

Explanation:

The coefficients are the key.

Create a proportion with them, and the molar mass, and then solve for x:

\frac{2}{3}  =  \frac{x}{28}  \\ 3x = 2(28) \\ 3x = 56 \\ x = 18.666... = 18.7

7 0
4 years ago
What is the molarity of 4 qof NaCl (MM=58.45) in 3,800 mL of solution?
tiny-mole [99]

Answer:

.018 M

Explanation:

grams/MM=ans./volume(L) = M

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8 0
3 years ago
To which group of alcohols does 3,4-dimethyl-2-pentanol belong?
dsp73

Answer:

The answer is A

Explanation:

8 0
3 years ago
How many moles of carbon are in 7.00 x 1023 atoms of carbon?
Andru [333]

Answer:

<h2>1.16 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{7}{6.02}  \\  = 1.162790....

We have the final answer as

<h3>1.16 moles</h3>

Hope this helps you

8 0
3 years ago
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