Answer is gas for sure and I think it’s ice for question 2
B. 6 atoms of carbon C
I would think this is the answer, because one can't just delete or add atoms; otherwise, the equation would be unbalanced. This also abides with the Law of Conservation of Mass.
Plus, I also came to that conclusion because if we look at the net equation of photosynthesis:

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The number of Carbon atoms is 6 on both the reagent's side and the product's side.
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Answer:</h3>
61.3 mL
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Explanation:</h3>
From the data given;
- Mass of volumetric flask is 109.1 g
- Mass of salt is 5.01 g
- Mass of Volumetric flask and salt is 113.5 g
- Mass of volumetric flask and salt solution is 170.4 g
- Mass of salt solution is 61.3 g
We are required to calculate the volume of salt solution;
We need to know the relationship between density, mass and volume of a solution.
Density = Mass ÷ Volume
Therefore, given mass and density we can find the volume.
Rearranging the formula;
Volume = Mass ÷ density
Assuming the density of salt solution is 1 g/mL
Then;
Volume = Mass of the salt solution ÷ density of the salt solution
= 61.3 g ÷ 1 g/mL
= 61.3 mL
Therefore, the volume of the salt solution is 61.3 mL
Answer:
K loses one electron to CI
Explanation:
The lewis electron dot notation shows only the chemical symbol of the element surrounded by dots to represent the valence electrons.
We have atom of K with one valence electrons
Cl with 7 valence electrons
For an electrostatic attraction to occur, both particles must be charged. To do this, one of the species must lose an electron, and the other gains it.
This will make both species attain a stable octet;
Hence, K will lose 1 electron and Cl will gain the electrons.
Answer:- Volume of the gas in the flask after the reaction is 156.0 L.
Solution:- The balanced equation for the combustion of ethane is:

From the balanced equation, ethane and oxygen react in 2:7 mol ratio or 2:7 volume ratio as we are assuming ideal behavior.
Let's see if any one of them is limiting by calculating the required volume of one for the other. Let's say we calculate required volume of oxygen for given 36.0 L of ethane as:

= 126 L 
126 L of oxygen are required to react completely with 36.0 L of ethane but only 105.0 L of oxygen are available, It means oxygen is limiting reactant.
let's calculate the volumes of each product gas formed for 105.0 L of oxygen as:

= 60.0 L 
Similarly, let's calculate the volume of water vapors formed:

= 90.0 L 
Since ethane is present in excess, the remaining volume of it would also be present in the flask.
Let's first calculate how many liters of it were used to react with 105.0 L of oxygen and then subtract them from given volume of ethane to know it's remaining volume:

= 30.0 L 
Excess volume of ethane = 36.0 L - 30.0 L = 6.0 L
Total volume of gas in the flask after reaction = 6.0 L + 60.0 L + 90.0 L = 156.0 L
Hence. the answer is 156.0 L.