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Shalnov [3]
3 years ago
12

If the volume of 0.100M HCl delivered to 10.0mL of NaOH is 12.0mL the NaOH concentration is

Chemistry
1 answer:
iVinArrow [24]3 years ago
3 0
<span>During neutralization reaction Milliequivalent of acid=milliequivalent of base. Milliequivalent of HCl=0.100*12*1 Milliequivalent of NaOH=M*10*1 So 0.100*12*1=M*10*1 Solve for M.</span>
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If a piece of cadmium with a mass of 37.60 g and a temperature of 100.0 oC is dropped into 25.00 cc of water at 23.0 oC, what wi
zlopas [31]

Answer:

T_{eq}=28.9\°C

Explanation:

Hello!

In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

Q_{Cd}+Q_{W}=0

Thus, we insert mass, specific heat and temperatures to obtain:

m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}

Now, we plug in to obtain:

T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

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6 0
3 years ago
Which of these have the same number of particles as 1 mole of water H2O
Fed [463]

Answer:

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Explanation:

The question is not very much clear.

If you are asking for molecules then 1 mole water= 6.023 * 10^23

If you are asking for atoms then 1 mole water= 6.023 * 10^23 * 3

If you are asking for particles then,

So, in your example you would have one mole of water molecules. If you dissociated those water molecules, than you would end up with 2 moles of hydrogen atoms, and one mole of oxygen atoms.

I hope that was helpful!

H=1 proton,1 electron

O=8 protons,8 neutrons and 8 electrons

total particles in one H2O molecule-28

total no. of particles in 1 mole of water- 6.023 * 10^23 * 28

8 0
3 years ago
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GenaCL600 [577]

Answer:

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Explanation:

5 0
3 years ago
If you had 0.681 moles of caso4.2h2o, how many moles of h2o would you have?
IgorLugansk [536]
The answer is 0.008 moles
7 0
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The mass of an atom is measured in a unit named the<br> ____. fill in the blank please helpppp
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