Answer:
75% chance of having four normal phenotype children without albinism.
50% chance of having four children who are carriers of the gene with normal phenotype.
Explanation:
Albinism results from an autosomal recessive gene. In order to solve this problem we have to draw a punnet square and figure out the genotypes of the parents. So with the genotype of the parents both parents have to be carriers of the trait since it is an autosomal recessive trait.
Genotype of female I-1 = Aa
Genotype of male I-1 = Aa
PARENTS A a
A AA Aa
a Aa aa
75% chance of having four normal phenotype children without albinism.
50% chance of having four children who are carriers of the gene with normal phenotype.
25% chance of having children with albinism.
Answer:
Explanation:
1) potential because it is not "in motion"
They use evidences. Hope it helps
The density and variety of receptors vary in different regions. For example, in hairy skin the peritrichial endings are most common, but Merkel's discs and free nerve endings are also present. In glabrous (hairless) skin, free nerve endings are present, as are Merkel's discs and Meissner's corpuscles.
Answer:
The simplest method of propagating a tree vegetatively is rooting or taking cuttings. A cutting (usually a piece of stem of the parent plant) is cut off and stuck into soil.
Remove any flowers or fruit on the cutting. Trim the stem to just below where the bottom most leaf meets the stem. On each of the leaves on the stem, cut off half of the leaf. Put the end to be rooted.
