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3 years ago

Which word phrases can be modeled by the expression?

Mathematics

2 answers:

tensa zangetsu [6.8K]3 years ago

6 0

A) (x÷7)-10
B) 7x -10
C) (x-10)÷7
D) (x÷7)-10

A and D are the same

kumpel [21]3 years ago

4 0

I'm not sure but I'll try and figure this out.

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Which of the following is true of the location of an angle, Theta, whose tangent value is Negative StartFraction StartRoot 3 End

Anuta_ua [19.1K]

The value of theta has a 30-degree reference angle and is located in Quadrant II or IV.

Given to us

$tan \theta =-\dfrac{\sqrt{3}}{3}$

<h3>What is the value of $tan \theta =\dfrac{\sqrt{3}}{3}$ ?</h3>

To know the value $tan \theta =\dfrac{\sqrt{3}}{3}$ we will simplify the given expression,

$tan \theta =\dfrac{\sqrt{3}}{3}\\\\\\tan \theta =\dfrac{1}{\sqrt{3}}\\\\tan \theta =30^o$

Hence, the value of theta is 30°.

<h3>Finding the location of the - tan30°?</h3>

To know that the location of the -tan30°,

$tan30^o = -\dfrac{sin30^o}{cos30^o}$

As the value is negative, therefore, there can be two cases,

Case I: when the value of Sin30° is negative,

Case II: when the value of cos30° is negative.

Case I: when the value of Sin30° is negative,

If the value of Sin30° is negative, while the value of cos30° is positive, the θ will lie in the fourth quadrant.

Case II: when the value of Cos30° is negative,

If the value of Cos30° is negative, while the value of Sin30° is positive, the θ will lie in the second quadrant.

Hence, the value of theta has a 30-degree reference angle and is located in Quadrant II or IV.

Learn more about Quadrants:

brainly.com/question/350459

5 0

3 years ago

Pls help

Shtirlitz [24]

It is B. 45 hope this helps

6 0

4 years ago

Jasper has an annual salary of $71,000, and his company pays him twice a month. What is the gross income per paycheck that Jaspe

Elan Coil [88]

Divide $71,000 by 24 because there are 12 months in a year and he gets paid 2 times a month. I got $2,958.33

5 0

4 years ago

Read 2 more answers

Please help me out with this!!<br> BRAINLIEST AVAILABLE!!

lapo4ka [179]

Answer:

xy = 1

k = 79

Step-by-step explanation:

Question One

The first and third frames look to me to be the same. I'll treat them that way.

y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6

2y + 6 = 2(x + 3) Remove the brackets

2y + 6 = 2x + 6 Subtract 6 from both sides

2y = 2x Divide by 2

y = x

Now solve these two equations.

so x^2 = x

x > 0

1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is

x(x) = x Divide both sides by x

x = 1

y = x^2 Put x = 1 into x^2

y = 1^2 Solve

y = 1

The second solution is

(1,1)

xy = 1*1

xy = 1

Answer: A

Question Two

square root(k + 2) - x = 0

Subtract x from both sides

sqrt(k + 2) = x Square both sides

k + 2 = x^2 Let x = 9

k + 2 = 9^2 Square 9

k + 2 = 81

k = 81 - 2

k = 79

4 0

3 years ago

Every hour of driving uses

xenn [34]

Answer:

45 gallons

Step-by-step explanation:

1 hour = 3 gallons

2 hours = 6 gallons

3 hours = 9 gallons

4 hours = 12 gallons

5 hours = 15 gallons

10 hours = 30 gallons

15 hours = 45 gallons

4 0

4 years ago