The nearest whole number would be 96
Step-by-step explanation:
According to this description we need a number that can be divided by 2,3 and 4 since the amount of rocks can be described by a natural number. However if a number is divided by 4 it is divided by 2 as well since 2*2=4.

If α is a natural number then 2*α is a natural number as well as the product of two natural numbers.
Which means that we need a number devided by 3 and 4.
The smallest number that fulfills this demand is 3*4=12.
Also any product of 12 with any natural number can be devided by 3, 4 and 2.
If the exercise asks for the numbers that are divided only by 2,3 and 4 these are:

Answer:
R = 118
Step-by-step explanation:
Given
Represent the polynomial with P and the divisor with D


Required
Determine the remainder
We start by equating the divisor to 0
i.e.



Substitute 2 for x in the polynomial.
This gives remainder (R)




<em>Hence, the remainder is 118</em>
It should be 44 if it goes up to 1,10. If it is 1,5 it should end up as 44 As well. Sorry if I’m wrong. Please do not attack me.
Answer:
The solution is where the two lines intersept. Therefore, the answer is (4,2).
Step-by-step explanation:
I hope this helps.