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julia-pushkina [17]
3 years ago
15

A coin is tossed and a spinner with three equal-sized sections labeled 3, 6, and 9 is spun. What is the probability of getting h

eads and a number greater than 3? Express as a fraction in simplest form.
Mathematics
2 answers:
Mariana [72]3 years ago
4 0

Answer:

The answer is 1/3.

Step-by-step explanation:

A coin has either heads or tails. The odds of a coin getting heads is 1/2.

There are three equal-sized sections with numbers 3, 6 and 9 on the spinner. There are two sections with numbers greater than 3, which are 6 and 9. The odds of getting a number greater than 3 is 2/3.

To find the overall probability of both incidents occurring, the two fractions are multiplied together, which is 1/2 * 2/3 = 1/3

DedPeter [7]3 years ago
4 0

Answer:

0.333/1/3

Step-by-step explanation:

Well, the probability of getting heads is 1/2 since there are 2 sides to a coin. There are 2 numbers on the spinner greater than three (6,9) which is 2/3.

1/2 times 2/3=0.33. The probability of getting heads and getting a number that is greater than is 0.333 or 1/3.

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Tamiku [17]

Answer:

We are to find the error made by Sadie and then find the correct simplification.

The error Sadie made is that she wrote a^7 as a^2 * a^5 instead of a^6 * a.

The square root of a^6 is a^3 and so she could have further simplified.

The correct simplification is shown below:

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Rudik [331]
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