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julia-pushkina [17]
3 years ago
15

A coin is tossed and a spinner with three equal-sized sections labeled 3, 6, and 9 is spun. What is the probability of getting h

eads and a number greater than 3? Express as a fraction in simplest form.
Mathematics
2 answers:
Mariana [72]3 years ago
4 0

Answer:

The answer is 1/3.

Step-by-step explanation:

A coin has either heads or tails. The odds of a coin getting heads is 1/2.

There are three equal-sized sections with numbers 3, 6 and 9 on the spinner. There are two sections with numbers greater than 3, which are 6 and 9. The odds of getting a number greater than 3 is 2/3.

To find the overall probability of both incidents occurring, the two fractions are multiplied together, which is 1/2 * 2/3 = 1/3

DedPeter [7]3 years ago
4 0

Answer:

0.333/1/3

Step-by-step explanation:

Well, the probability of getting heads is 1/2 since there are 2 sides to a coin. There are 2 numbers on the spinner greater than three (6,9) which is 2/3.

1/2 times 2/3=0.33. The probability of getting heads and getting a number that is greater than is 0.333 or 1/3.

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The perimeter of the new m-phone is 16 inches. The phones length is 5.25 inches. What is the width of the phone
True [87]
Perimeter is all the sides added up together.
Divide 16 by 2, so that you can get just a measurement of the length and the width.

16/2 = 8

Since the length is 5.25, subtract that by 8.

8-5.25 = 2.75

The width of the phone is 2.75 inches.
5 0
3 years ago
Can you round 14.392
seropon [69]

Answer:

the rounded answer is 14

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which set of parametric equations over the interval 0 ≤ t ≤ 1 defines a line segment with initial point (–5, 3) and terminal poi
Ksivusya [100]

Given:

A line segment with initial point (–5, 3) and terminal point (1, –6).

To find:

The set of parametric equations over the interval 0 ≤ t ≤ 1 which defines the given line segment.

Solution:

Initial point is (–5, 3). So,

x(0)=-5,y(0)=3

Terminal point is (1, –6).

x(1)=1,y(1)=-6

Check which of the given set of parametric equations satisfy x(0)=-5,y(0)=3,x(1)=1,y(1)=-6.

Put t=1 in each set of parametric equations.

In option A,

y(1)=3-6(1)=3-6=-3\neq -6

So, option A is incorrect.

In option B,

y(1)=1-6(1)=1-6=-5\neq -6

So, option B is incorrect.

In option C,

y(1)=3-9(1)=3-9=-6

x(1)=-5+6(1)=-5+6=1

Put t=0, in this set of parametric equations.

x(0)=-5+6(0)=-5

y(0)=3-9(0)=3

So, option C is correct.

In option D,

y(1)=1-7(1)=1-7=-3\neq -6

x(1)=-5+8(1)=-5+8=3\neq 1

So, option D is incorrect.

8 0
3 years ago
The speed, s, of the current in a certain whirlpool is modeled by s=300/d, where d is the distance from the center of the whirlp
JulijaS [17]
For this case we have the following equation:
 s = 300 / d
 Where,
 s: the speed of the current in a certain whirlpool
 d: the distance from the center of the whirlpool
 We have then that:
 If the distance from the center of the whirpool is large, the speed is small.
 If the distance from the center of the whirlpool is very small, the speed tends to infinity
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Large distance, small speed.
 
Short distance, speed tends to infinity.
7 0
3 years ago
Read 2 more answers
4x-5y=-3
tresset_1 [31]
4x - 5y = -3  ⇒ 1st equation
2x + 3z = 4  ⇒ 2nd equation
3y - z = 8     ⇒ 3rd equation

find the value of z.

3y - z = 8
- z = 8 - 3y
z = (8 - 3y) / -1
z = -8 + 3y

Substitute z with its value in the 2nd equation:
2x + 3z = 4
2x + 3(-8 + 3y) = 4
2x - 24 + 9y = 4
2x + 9y = 4 + 24
2x + 9y = 28

find value of x
2x + 9y = 28
2x = 28 - 9y
x = (28 - 9y)/2
x = 14 - 9y/2

Substitute the value of x in 1st equation
4x - 5y = -3
4(14-9y/2) - 5y = -3
56 - 36y/2 - 5y = -3
- 36y/2 - 5y = -3 - 56
- 36y/2 - 5y = - 59
2(-36y/2 - 5y) = 2(-59)
-36y - 10y = -118
-46y = -118
-46y/-46 = -118/-46
y = 2 26/46
y = 2 13/23  

x = 14 - 9y/2
x = 14 - 9 (2 13/23) /2
x = 14 - 9 (59/23) / 2
x = 14 - 531/23 / 2
x = 14 - 531/23 * 1/2
x = 14 - 531/23*2
x = 14 - 531/46
x = (14*46/46) - 531/46
x = 644/46 - 531/46
x = (644-531)/46
x = 113/46
x = 2 21/46

z = -8 + 3y
z = -8 + 3(2 13/23)
z = -8 + 3(59/23)
z = -8 + 177/23
z = (-8*23/23) + 177/23
z = -184/23 + 177/23
z = (-184 + 177)/23
z = -7/23

x = 2 21/46 ; y = 2 13/23 ; z = -7/23

4x - 5y = -3
4(113/46) - 5(59/23) = -3
452/46 - 295/23 = -3
9.826 - 12.826 = -3
-3 = -3

2x + 3z = 4
2(113/46) + 3(-7/23) = 4
226/46 - 21/23 = 4
4.913 - 0.913 = 4
4 = 4

3y - z = 8
3(59/23) - (-7/23) = 8
177/23 + 7/23 = 8
7.696 + 0.304 = 8
8 = 8 

8 0
3 years ago
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