Wow ! There's so much extra mush here that the likelihood of being
distracted and led astray is almost unavoidable.
The circle ' O ' is roughly 98.17% (π/3.2) useless to us. The only reason
we need it at all is in order to recall that the tangent to a circle is
perpendicular to the radius drawn to the tangent point. And now
we can discard Circle - ' O ' .
Just keep the point at its center, and call it point - O .
-- The segments LP, LQ, and LO, along with the radii OP and OQ, form
two right triangles, reposing romantically hypotenuse-to-hypotenuse.
The length of segment LO ... their common hypotenuse ... is the answer
to the question.
-- Angle PLQ is 60 degrees. The common hypotenuse is its bisector.
So the acute angle of each triangle at point ' L ' is 30 degrees, and the
acute angle of each triangle at point ' O ' is 60 degrees.
-- The leg of each triangle opposite the 30-degree angle is a radius
of the discarded circle, and measures 6 .
-- In every 30-60 right triangle, the length of the side opposite the hypotenuse
is one-half the length of the hypotenuse.
-- So the length of the hypotenuse (segment LO) is <em>12 </em>.
80 adult, 50 child. Got answer by trial and error, so no clue as to how to get the answer using any formula.
13x + 1 = 11x + 8
First, subtract 1 from both sides. / Your problem should look like: 13x = 11x + 8 - 1
Second, simplify 11x + 8 - 1 to 11x + 7. / Your problem should look like: 13x = 11x + 7
Third, subtract 11x from both sides. / Your problem should look like: 13x - 11x = 7
Fourth, simplify 13x - 11x to 2x. / Your problem should look like: 2x = 7
Fifth, divide both sides by 2. / Your problem should look like: x =
Answer:
x = Answer in decimal form: 3.5
Answer: 0.67%/min or 40%/hr
Step-by-step explanation:
In 30minutes It charges 20%, in 1 minute, it will charge 20/30 = 0.6666
In 1hr it will charge 40%, twice the amount it charged in 30minutes (From 35 to 55)