Use the chart to multiply the binomial by the trinomial.

Mathematics

2 answers:

PSYCHO15rus [73]3 years ago

8 0

Answer:

The result of the multipy the binomial by the trinomial is y^3+27.

Step-by-step explanation:

To complete the empty spaces of the chart we multipy the term of the row with the term of the column.Then we sum each monomial of the chart:

y^3-3y^2+9y+3y^2-9y^2+27 = y^3+0y^2+0y+27 = y^3+27

sukhopar [10]3 years ago

5 0

Answer: " -2y³ + 3y²<span> + 27y " .
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Refer to the completed chart below (image attached).</span>
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Using the completed chart below (image attached), we can write out the terms:
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y³ − 3y³ + 9y² + 3y² − 9y² + 27y ;

Then, we can combine the "like terms" ;
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y³ − 3y³ = -2y³ ;

+9y² + 3y² − 9y² = + 3y² ;
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to get: -2y³ + 3y² ; and bring down the "+27y" ;
___________________________________________________________
Answer: " -2y³ + 3y²<span> + 27y " . </span>Refer to chart below (image attached).
___________________________________________________________

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Step-by-step explanation:

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Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$