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hram777 [196]
3 years ago
14

A _______ occurs when access to a website is interrupted because there are to many simultaneous requests, and result in a ______

_ when the time limit for accessing the resource is reached.
Blank 1: Denial of Service or Timeout

Blank 2: Denial of Service or Timeout
Computers and Technology
1 answer:
rjkz [21]3 years ago
3 0

Answer:time out then denial of service

Explanation:

Cause I did it.

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What is the service provided by a third party (such as an ISP) that enables you to connect another cloud directly to your Google
Olenka [21]

Answer:

A. Dedicated interconnect

Explanation:

With dedicated interconnect, there is a direct connection between your network and that of Google. It enables you to connect another cloud directly to your Google cloud resources to create hybrid cloud solutions. In other words, Dedicated Interconnect enables hybrid networking. Businesses can now extend their own private cloud into Google's cloud so they can switch control between the two with little latency. This gives them (businesses) control over the amount of data entering into the two clouds.

8 0
3 years ago
Write a program that reads numbers from a file (or allow user to input data) and creates an ordered binary tree. The program sho
IgorLugansk [536]

Answer:

See explaination

Explanation:

include<bits/stdc++.h>

using namespace std;

typedef struct Node

{

int data;

struct Node *left,*right;

}Node;

bool search(Node *root,int data)

{

if(root==NULL)

return false;

if(root->data==data)

return true;

queue<Node*> q;

q.push(root);

while(!q.empty())

{

Node *temp=q.front();

q.pop();

if(temp->data==data)

return true;

if(temp->left)

q.push(temp->left);

if(temp->right)

q.push(temp->right);

}

return false;

}

Node *insert(Node *root,int data)

{

if(root==NULL)

{

Node *temp=new Node();

temp->data=data;

temp->left=NULL;

temp->right=NULL;

return temp;

}

if(data < root->data)

root->left=insert(root->left,data);

if(data>root->data)

root->right=insert(root->right,data);

return root;

}

Node *get_smallest_element_right_subtree(Node *root)

{

while(root && root->left!=NULL)

root=root->left;

return root;

}

Node *delete_node(Node *root,int data)

{

if(root==NULL)

return root;

if(data < root->data)

root->left=delete_node(root->left,data);

else if(data > root->data)

root->right=delete_node(root->right,data);

else

{

if(root->left==NULL) //If right only presents means - delete the curr node and return right node

{

Node *temp=root->right;

free(root);

return temp;

}

else if(root->right==NULL) //If left only presents means - delete the curr node and return let node

{

Node *temp=root->left;

free(root);

return temp;

}

else

{

Node *temp=get_smallest_element_right_subtree(root->right);

root->data=temp->data;

root->right=delete_node(root->right,temp->data);

}

return root;

}

}

void inorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

cout<<root->data<<" ";

inorder(root->right);

}

}

void postorder(Node *root)

{

if(root!=NULL)

{

inorder(root->left);

inorder(root->right);

cout<<root->data<<" ";

}

}

void preorder(Node *root)

{

if(root!=NULL)

{

cout<<root->data<<" ";

inorder(root->left);

inorder(root->right);

}

}

int main()

{

fstream f;

string filename;

cout<<"\n\n1 - Input through File ";

cout<<"\n\n2 - Input through your Hand";

int h;

cout<<"\n\n\nEnter Your Choice : ";

cin>>h;

Node *root=NULL; // Tree Declaration

if(h==1)

{

cout<<"\n\nEnter the Input File Name : ";

cin>>filename;

f.open(filename.c_str());

if(!f)

cout<<"\n\nError in Opening a file !";

else

{

cout<<"\n\nFile is Being Read ........";

string num;

int value;

int node=0;

while(f>> num)

{

value=stoi(num);

root=insert(root,value);

node++;

}

cout<<"\n\nTree has been successfully created with : "<<node<<" Nodes"<<endl;

}

}

if(h==2)

{

int y;

cout<<"\n\nEnter the Total No of Input :";

cin>>y;

int i=1,g;

while(i!=y+1)

{

cout<<"\n\nEnter Input "<<i<<" : ";

cin>>g;

root=insert(root,g);

i++;

}

cout<<"\n\nTree has been successfully created with : "<<y<<" Nodes"<<endl;

}

if(h>=3)

{

cout<<"\n\nInvalid Choice !!! ";

return 0;

}

int n=0;

while(n!=6)

{

cout<<"\n\n\n1 - Insert Element";

cout<<"\n\n2 - Remove Element";

cout<<"\n\n3 - Inorder (LNR) Display ";

cout<<"\n\n4 - Pre (NLR) Order Display";

cout<<"\n\n5 - Post (LRN) Order Display";

cout<<"\n\n6 - Quit";

cout<<"\n\nEnter Your Choice : ";

cin>>n;

switch(n)

{

case 1:

{

int k;

cout<<"\n\nEnter Element to insert : ";cin>>k;

root=insert(root,k);

cout<<"\n\nElement Sucessfully Inserted !!!!!";

break;

}

case 2:

{

int k;

cout<<"\n\nEnter Element to Remove : ";

cin>>k;

if(search(root,k))

{

root=delete_node(root,k);

cout<<"\n\nValue Successfully Deleted !!!";

}

else

cout<<"\n\n!!!!!!!!!!!!!!!!!!!! No Such Element !!!!!!!!!!!!!!!!!!!!!!";

break;

}

case 3:

{

cout<<"\n\nThe Elements (LNR) are : ";

inorder(root);

break;

}

case 4:

{

cout<<"\n\nThe Elements (NLR) are : ";

preorder(root);

break;

}

case 5:

{

cout<<"\n\nThe Elements (LRN) are : ";

postorder(root);

break;

}

case 6:

{

break;

}

}

}

cout<<"\n\nBye!!!! See You !!!"<<endl;

7 0
3 years ago
If a pedestrian begins to cross my path when i have the right of way
Daniel [21]
What exactly is your question?? If you are driving all pedestrians have the right way.....treat all intersections as a crosswalk painted or not!!!
3 0
3 years ago
Assuming a computer has a single processor and a single core with no support for parallel execution, explain why running a multi
IRISSAK [1]

Answer:

Explanation:

Before we go deep into this question lets have some brief knowledge on parallel execution, parallel processing and multi tasking.

Parallel Execution : in this two or more tasks or program can be executed parallel or simultaneously.

For example if there are two processors and four programs to be executed then it executes two at a time.

Multi tasking: in this two or more tasks can be performed simultaneously switching between them without exiting any application.

For example we use notepad, word pad, excel sheet, chrome all at a time switching between each other.

Multi Threading: It is splitting up the program into different threads.If the contents in the program are independent on each other then the program can be split into multi threads and can be processed.

Multi threading in multi core or processing unit : In this threads are executed parallel or simultaneously in different processes.

For example if there are two processors then one multi threaded program can execute two threads in two different processors.

Multi threaded program in single core unit : In this, program is multi threaded where as threads cannot execute parallel or simultaneously. they sholud be executed by the same processor. So they should wait in queue

Ex: consider three tasks of 6 secs each and multi threaded each into three threads of two seconds.

Task1 3secs > task2 3secs > task3 3 secs it repeats until each task is completed

Total time taken is 3+3+3+3+3+3+3+3+3 is 18seconds...

If they are executed one by one without multi threading total execution time has no change..

Where as multi threading program has its advantages if different threads are executed at different place..

If one thread executes at network, another at printer and other processor then these three can execute at same time at different processors. Multi threading has its advantages but in single core systems it doesn't affect the performance.

Inter process communication consists of

Information Sharing, message passing, Modularity.

In shared memory inter process communication processes shares the memory between each other.

In message passing communication process communicates like request and replies for information and resources.

Interlocking is due to error in resource sharing and information sharing. It results in system collapse.

Al these process communication is required if there are two or more.processes but in single core it is not much useful and advisable.

In single core there will be a single processor, processing multi threaded program as it can access all the memory contents there will be no problem of process communication. Where as in multi core systems different processes may compete for same memory or resource.

In single core systems inter process communication makes things complex and these complexity is not much useful in any of the improvement in performance.

4 0
3 years ago
The physical address assigned each network adapter is called its ________.
zysi [14]
MAC address
....................
5 0
3 years ago
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