Answer:
Explanation:
a) taking 00000005, it is a 13th bit which is 0, and therefore, we'd call it an ordered chunk
b) taking 00000005 again, it is 14th (B) and 15th (E) bits are 0 and so we'd call it a middle fragment
c) 00000015 is equal to 21, it is not a multiple of 4, and as such, it needs 3 padding bytes
d) 00000005 is equal to 5 making it a TSN. So the TSN is 5
e) taking 0003, we can then say the SI is 3
f) taking 000A, the SSN is then 10
g) the message is 48656C6C
The loop terminates when "xxxxx" is read in. If the word is land, the string followed by "land" get outputted. The same with air, and water.
Explanation:
int land = 0;
int air = 0;
int water = 0;
String word = "";
while(!(word.equals("xxxxx"))) {
word = stdin.next();
if(word.equals("land")) {
land++;
}else if(word.equals("air")) {
air++;
}else if(word.equals("water")) {
water++;
}
}
System.out.println("land:" + land);
System.out.println("air:" + air);
System.out.println("water:" + water);
An instance in my life where I rendered services was when I worked in a grocery store.
The roles of entrepreneur include:
- Allocating employees duties.
- Improving standard of living.
- Taking risks.
The three challenges that a young entrepreneur faces today include:
- Financial instability.
- Conflicts with education.
- Lack of business skills.
The top three characteristics of an entrepreneur include:
- Innovation.
- Confidence
- Risk taking
<h3>Who's an entrepreneur?</h3>
It should be noted that a entrepreneur is an individual who owns business and take risks.
The roles of entrepreneur include allocating employees duties, improving standard of living, and taking risks
Learn more about entrepreneur on:
brainly.com/question/353543
#SPJ1
Answer:
Latency of an object O is shown below.
Explanation:
W segment and stalled state transmits nothing and waits for acknowledgement. The latency is 2 R TT + the time required for server that are using to transmit the object + the amount of time when server is in stalled state. Let K be the number of window that is K= O/WS .The serveries stalled state where K-1 is period of ime with period lasting RTT-(W-1)S/R
latency = 2RTT +O/R +(K-1)[S/R +RTT - WS/R]
After combining the two case
latency = 2 RTT + O/R + (K-1)[S/R +RTT - WS/R]
where [x] means maximum of (x.0). This is the complete ananlysis of the static windows.
server time for transmit the object is (K-1)[S/R +RTT - WS/R]
B) each person gets to contribute in their own unique way
