Question

Ardem collected data from a class survey. He then randomly selected samples of five responses to generate four samples.

Answer 1

Solution: The sample mean of sample 1 is:

$\bar{x}=\frac{4+5+2+4+3}{5}= \frac{18}{5}=3.6$

The sample mean of sample 2 is:

$\bar{x}=\frac{2+2+6+5+7}{5}= \frac{22}{5}=4.4$

The sample mean of sample 3 is:

$\bar{x}=\frac{4+6+3+4+1}{5}= \frac{18}{5}=3.6$

The sample mean of sample 4 is:

$\bar{x}=\frac{5+2+4+3+6}{5}= \frac{20}{5}=4$

The minimum sample mean of the four sample means is 3.6 and maximum sample mean of the four sample means is 4.4.

Therefore, using  his four samples, between 3.6 and 4.4 will Ardem's actual population mean lie.

Hence the option 3.6 and 4.4 is correct

Answer 2

Answer: between 3.6 and 4.4

Step-by-step explanation: