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Kay [80]
3 years ago
12

Captain Prince already has 34 kills so far. He has been “playing” for 50 minutes. If he ends, with 146 kills, how many kills doe

s he have each minutes?
Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
6 0
2.92 kills per minute
cestrela7 [59]3 years ago
3 0
2.92 would be your answer to the question
You might be interested in
On the first
liubo4ka [24]

Answer:

0.93

Step-by-step explanation:

u have to add them all and divide by 12. then u add all of them but the outlier and divide by 11. then u subtract.

4 0
3 years ago
Identify whether the following
erik [133]
It opens downwards so it looks like this “n”. That is because a in the formula is a negative number in this situation
6 0
3 years ago
Please help! :) Need answer fast!
Vlada [557]

Answer:

x = 3

y = 2

Step-by-step explanation:

When 2 triangles are congruent, they will have exact same 3 sides length and exact same 3 angles measure.

So we can say:

-2x + 6y = 6

and

-7x + 8y = -5

Let's multiply first equation by 7 and 2nd equation by -2, to get:

7 [-2x + 6y = 6] = -14x +42y = 42

and

-2 [-7x + 8y = -5] = 14x - 16y = 10

Now adding these 2 new equations and solving for y:

-14x +42y = 42

14x - 16y = 10

----------------------

26y = 52

y = 52/26

y = 2

Now we put y = 2 into 1st equation (or any other) and solve for x:

-2x + 6y = 6

-2x + 6(2) = 6

-2x + 12 = 6

6 = 2x

x = 6/2

x = 3

5 0
3 years ago
Determine the first four terms of the sequence in which the nth term is...
Anon25 [30]

Answer:

1/5, 1/6, 1/7, 1/8

Step-by-step explanation:

The formula for the sequence is (n+3)!/ (n+4)!

The first terms uses n=1

a1 = (1+3)!/ (1+4)! = 4!/5! = (4*3*2*1)/(5*4*3*2*1) = 1/5


The first terms uses n=2

a2 = (2+3)!/ (2+4)! = 5!/6! = (5*4*3*2*1)/(6*5*4*3*2*1) = 1/6


The first terms uses n=3

a3 = (3+3)!/ (3+4)! = 6!/7! = (6*5*4*3*2*1)/(7*6*5*4*3*2*1) = 1/7


The first terms uses n=4

a4 = (4+3)!/ (4+4)! = 7!/8! = (7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1) = 1/8

7 0
3 years ago
Read 2 more answers
For which pair of functions is the vertex of k(x)7 units below the vertex of f(x)?
kvv77 [185]

Answer: Option C

f(x) = x^2;\ k (x) = x ^ 2 -7

Step-by-step explanation:

Whenever we have a main function f(x) and we want to transform the graph of f(x) by moving it vertically then we apply the transformation:

k (x) = f (x) + b

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units down.

If b> 0 then the graph of k(x) will be the graph of f(x) displaced vertically b units upwards.

In this case we have

f (x) = x ^ 2

We know that this function has its vertex in point (0,0).

Then, to move its vertex 7 units down we apply the transformation:

k (x) = f (x) - 7\\\\k (x) = x ^ 2 -7.

Then the function k(x) that will have its vertex 7 units below f(x) is

k (x) = x ^ 2 -7

3 0
3 years ago
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