y = -(1/2) sqrt(x + 3) Interchange the x and y
x = -(1/2) sqrt(y + 3) multiply through by - 2
-2x = sqrt(y + 3) Square both sides.
(-2x)^2 = (sqrt(y + 3))^2
4x^2 = y + 3 Subtract 3 from both sides.
y = 4x^2 - 3
The usual rule is to interchange the domain and range of the original equation with the inverse. The range of the original equation is 0 => y > -infinity.
If that is the case, then the domain of the inverse is 0<=x. The graph was revised and provided by Mathmate. It is the correct way to represent this function and it's inverse Including the fact that x<=0. That restriction is very important. The line is x = y and the graphs should reflect around that line.
X = -14
x+10-5=-9
x+5=-9
x=-14
X is the number
<span>The sum of two numbers is 11, so other number is : 11 - x
</span><span>The sum of their squares is 65
</span>
x^2 + (11 - x)^2 = 65
x^2 + 121 - 2(x)(11) + x^2 = 65
2x^2 - 22x + 121 = 65
2x^2 - 22x + 121 - 65 = 0
2x^2 - 22x + 56 = 0
2(x^2 - 11x + 28) = 0
2(x - 7)(x -4 ) = 0
x - 7 = 0
x = 7
x - 4 =0
x =4
answer: the numbers are 4 and 7
double check:
<span>sum of two numbers is 11:
4 + 7 = 11
</span><span>The sum of their squares is 65
</span><span>4^2 + 17^2 = 16 + 49 = 65
</span>
Answer:
Step-by-step explanation:
Given that angle A is in IV quadrant
So A/2 would be in II quadrant.
sin A = -1/3
cos A = 
(cos A is positive since in IV quadrant)
Using this we can find cos A/2
Answer:
-2a³+9a²+45a+6ab²+18b²
Step-by-step explanation:
(a+3)(-2a²+15a+6b²)
Distribute the a:
-2a³+15a²+6ab²
Then distribute the 3:
-6a²+45a+18b²
Now add both of the results together:
-2a³+15a²+6ab²-6a²+45a+18b²
Combine like terms:
-2a³+9a²+45a+6ab²+18b²
