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PolarNik [594]
3 years ago
10

I have another math question and another Brainliest for a math genius

Mathematics
2 answers:
PolarNik [594]3 years ago
7 0
#14 $281.65
#15 $352.08
#22 15
#23 52
Hope this helps!!

Dahasolnce [82]3 years ago
7 0
Attached the solution and work.

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Slope for y=5,520.619x - 1,091.393
Bad White [126]

Answer:

m = 5,520.619

Step-by-step explanation:

The given equation is :

y=5,520.619x-1,091.393 ....(1)

The general form of equation is given by :

y = mx +c ...(2)

Where

m is slope of line

c is y-intercept

Comparing equation (1) and (2), we get :

Slope, m = 5,520.619

Hence, the slope of the given line is 5,520.619.

3 0
3 years ago
Please solve and show work! Thanks!
notsponge [240]

Answer:

1) x < 1, x > 9

2) 2 < x ≤ 6, -4 ≤ x < 0

Step-by-step explanation:

1) lx - 5l > 4

x - 5 = 4

x = 9

-(x - 5) = 4

x = -4 + 5 = 1

x < 1, x > 9

3) 1 < lx-1l ≤ 5

1 < x-1 ≤ 5

2 < x ≤ 6

1 < -(x-1) ≤ 5

-5 ≤ x-1 < -1

-4 ≤ x < 0

6 0
3 years ago
Read 2 more answers
BRAINLIEST for whoever gets this correct!
ratelena [41]

Answer:

b

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
An ostrich can run at a rate of 50 miles in 60 minutes.At this rate,how long would it take an ostrich to run 15 miles?
just olya [345]
If an ostrich can run 50 miles in one hour then he can run 12.5 miles in 15 minutes. 15 minutes is 1/4 of an hour. Multiply 50 by 0.25 = 15.
3 0
3 years ago
A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The
TiliK225 [7]

Correct question:

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The company ships them to restaurants in boxes of 9 ​salmon, to grocery stores in cartons of 16 ​salmon, and to discount outlet stores in pallets of 64 salmon. To forecast​ costs, the shipping department needs to estimate the standard deviation of the mean weight of the salmon in each type of shipment. Complete parts​ (a) and​ (b) below.

a. Find the standard deviations of the mean weight of the salmon in each type of shipment.

b. The distribution of the salmon weights turns out to be skewed to the high end. Would the distribution of shipping weights be better characterized by a Normal model for the boxes or pallets?

Answer:

Given:

Mean, u = 44

Sd = 3

The company ships in boxes of 9, cartons of 16 and pallets of 64.

a) For the standard deviations of the mean weight of the salmon in each type of shipment, lets use the formula: \frac{s.d}{\sqrt{u}}

i) For the standard deviation of the mean weight of salmon in boxes of 9, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{9}}

= \frac{3}{3} = 1

The standard deviation = 1

ii) For the standard deviation of the mean weight of salmon in cartons of 16, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{16}}

= \frac{3}{4} = 0.75

Standard deviation = 0.75

iii) For the standard deviation of the mean weight of salmon in pellets of 64, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{64}}

= \frac{3}{8} = 0.375

Standard deviation = 0.375

b) The distribution of shipping weights would be better characterized by a Normal model for the pallets, because regardless of the underlying distribution, the sampling distribution of the mean approaches the Normal model as the sample increases.

5 0
3 years ago
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