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3 years ago

12

Ed had a gross income of $3255.29 during each pay period in 2010. If he got paid monthly, how much of his pay was deducted for F

ICA in 2010

2 answers:

ad-work [718]3 years ago

8 0

Answer:

$2988.36

Step-by-step explanation:

pogonyaev3 years ago

5 0

If you start and the begging of the year and the end and how much you make and at the end of the year you will know our income.

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This math question is hard. Help Me Pls

devlian [24]

Answer:

solution is: plus -2

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3 years ago

4(4x+1) = 3x-4(6-x) + 4

brilliants [131]

the answer is -2.2.

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3 years ago

Read 2 more answers

4) During a school carnival, students from the middle school raised money by selling crafts, food, game tickets, and school play

ioda

$225 was earned from the craft sales

and $40 was earned from the play.

Given, During a school carnival, students from the middle school raised money by selling crafts, food, game tickets, and school play admissions.

Of each dollar earned, $0.15 came from games. Craft sales earned 3 times as much as games. Food sales were 4 times the amount earned from the play.

Let the amount earned by play be x,

Now, Games earned = 0.15×500 = $75

Also, crafts earned 3×75 = $225

Now, as play earned x, then food earned 4x.

According to question,

x + 75 + 225 + 4x = 500

5x + 300 = 500

5x = 200

x = 40

So, the amount earned by Play be, $40

and the amount earned by Food be $160.

Hence, $225 was earned from the craft sales

and $40 was earned from the play.

Learn more about Linear Equations here brainly.com/question/24085666

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1 year ago

Jackson mom limits the amout of time he is allowed to play video games . After jackson play for 9 .Inutes , his mom tells him th

vaieri [72.5K]

If we know that 30% of the time is used after 9 minutes we can write this mathematically as:

$0.30x = 9$
By solving for x we can determine the total time allowed to play games and so:

$x = \frac{9}{0.30} = 30$
The total time allowed to play games is 30 minutes. Since 9 minutes have lapsed 30-9=21 minutes left to play.

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2

Nimfa-mama [501]

First of all, we can observe that

$x^2-6x+9 = (x-3)^2$

So the expression becomes

$\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}$

This means that the expression is defined for every $x\neq 3$

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

$x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2$

Since we can't accept 3 as an answer, the actual solution set is

$(-\infty,-2] \cup [2,3) \cup (3,\infty)$

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3 years ago