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3 years ago

A rectangle has length x cm and width 2 cm less

Mathematics

2 answers:

vichka [17]3 years ago

7 0

x^2 - 2x = 146

x^2 - 2x - 146 = 0

See attachment. The quadratic formula is needed in this case.

Gennadij [26K]3 years ago

4 0

I think you can just factor it out by taking x out of the left side of the equation

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Find the value of :[5x+y+z][5x+y+z][5x+y+z]

KIM [24]

Answer:

Step-by-step explanation:

(a + b + c)³ = a³ + b³ + c³ + 3a²b + 3a²c + 3ab² + 3cb² +3 ac² + 3bc² + 6abc

a = 5a ; b =y ; c = z

(5x + y + z)(5z + y + z )(5z + y +z) = (5x + y +z)³

= (5x)³ + y³ +z³ + 3(5x)²y + 3(5x)²z + 3(5x)*y² + 3*z*y² + 3*5x*z² + 3*y*z² + 6*5x*y*z

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3 years ago

If f(x) = 4x + 2, what is the value of f(3)? O 8 O 14 O 45 O 66

lutik1710 [3]

Answer:

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP ASAP!!

natka813 [3]

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3 years ago

I need help what's the value of 4^-5 ?

sasho [114]

Step-by-step explanation:

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3 years ago

What are the X and Y intercepts of y= -2(x-4)2 +3

kari74 [83]

Answer: x-intercepts are ( 2.775,0) and (5.225,0)

And y-intercept is (0,-29)

Step-by-step explanation:

Here the given equation is,

$y = -2(x-4)^2+3$

For x-intercept, y = 0,

Put y = 0 in the above equation of parabola,

We get, $-2(x-4)^2 + 3 = 0$

$-2(x^2+16+8x) + 3 = 0$

$-2x^2-32-16x + 3 = 0$

$-2x^2-16x -29 = 0$

By solving this equation,

We get, x = 2.775 or x = 5.225

Therefore, x-intercept of the given parabola are (2.775, 0) and (5.225,0)

Now, for y-intercept, x = 0

By putting x = 0 in the given equation of parabola,

We get, y = -29

Thus, y-intercept of the given parabola = (0,-29)

4 0

3 years ago