Answer:
332 ft²
Step-by-step explanation:
A rectangular garden measures 33 ft by 46 ft. Surrounding (and bordering) the garden is a path 2 ft. Find the area of this path. Be sure to include the correct unit in your answer.
Solution:
The area of the rectangular garden = length * breadth = 33 ft. * 46 ft. = 1518 ft²
Since the path surrounding the garden is 2ft, the length of the path with the garden = 46 + 2 + 2 = 50 ft
The width of the path with the garden = 33 + 2 + 2 = 37 ft.
Area of the path with the garden = length * breadth = 50 ft * 37 ft = 1850 ft².
Area of the path = 1850 ft² - 1518 ft.² = 332 ft²
The length and width of the rug is 20 and 11 feet respectively
The given parameters;
dimension of the room = 19 ft by 28 ft
maximum area of rug she can afford = 220 ft²
For a uniform stripe of floor around the rug, then suppose the uniform excess length of the floor to removed from each dimension = y
(28-2x)(19-2x)=220
532-94x+4x^2=220
4x^2-94x+312=0
x=39/2,4
For x=39/2, dimensions are negative.
The uniform dimension of the floor to be covered by the maximum area of rug she can afford = (28 - 4×2) and (19 -2×4 ) = 20 and 11
Thus, the dimensions of the rug should be 20 feet and 11 feet
- The area of a rectangle is length times breadth.
- Area is the total squares cm occupied by a closed figure.
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F(x) = x + 8
This is because you are simply moving the y-intercept up 8 units.
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Answer:
I think it is G
Step-by-step explanation:
So ya see, it really does peak at the given times.
