While the absorbance at 420 nm is related to the amount of o-nitrophenol produced, the absorbance at 600 nm is proportional to cell density, which aids in standardizing our estimations of enzyme activity.
<h3>Describe absorbance.</h3>
The amount of light absorbed by a solution is measured by its absorbance (A), often referred to as optical density (OD). The amount of light that may flow through a solution is called its transmittance.
<h3>How is the activity of beta-galactosidase determined?</h3>
The colorless ONPG substrate is changed by beta-Galactosidase into galactose and the chromophore o-nitrophenol, which results in a vivid yellow solution. The amount of substrate transformed at 420 nm can be calculated by measuring the solution's beta-galactosidase activity using a spectrophotometer or a microplate reader.
<h3>What is measured by the beta-galactosidase assay?</h3>
The -Gal Assay Kit gives users the tools they need to swiftly assess the amounts of active beta-galactosidase expressed in cells that have been transfected with plasmids encoding the lacZ gene.
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The cells are generally the same but animal cells don't have a cell wall and also there vacuole is smaller than plants
Type II restriction enzymes, such as Ecor I, that make staggered cuts within its recognition sequence, are considered more effective in biotechnology because they result in cohesive or sticky ends.
<h3>What is Ecor I and why are sticky ends important?</h3>
Ecor I is a kind of restriction enzyme which is obtained from Escherichia coli. The palindromic sequence recognized by this enzyme is 5' - GAATTC - 3'. It makes the following cuts between G and A on both the strands of the DNA to form sticky ends:
5' - G↓AATTC - 3'
3' - CTTAA↑G - 5'
Sticky ends are a fragment of DNA which is produced through a staggered cut, by the use of restriction enzyme. In this the terminal portion stretches with unpaired nucleotides. These kind of ends are easy to ligate when rDNA needs to be formed.
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Answer:
Option (e).
Explanation:
Blood is the main connective tissue of the body. Blood helps in the transport of oxygen, nutrients and the excretory product of the body. Blood also provides immunity as it contains white blood cells.
The resting time is expected during the diffusion process. But the substance continuous back and forth in the body. This is because cells are the main living entity of the organism. The cells are never at rest in order to live and their resting time is not possible.
Thus, the correct answer is option (e).
