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Hunter-Best [27]
3 years ago
12

Maurice has 76 postcards in all. The ratio of the number of postcards he has received to the number of postcards he has bought i

s 3:1. How many more postcards has Maurice received than bought?

Mathematics
1 answer:
nexus9112 [7]3 years ago
4 0

Answer:

50 but if its not an estimate 50.6 i would try 50 first

Step-by-step explanation:

also brainiest plz

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I need help on this one please
TiliK225 [7]

Hi

Income tax is  progressive

So with  50 000  we have  :  

0.02*3000 + 0.03 ( 5000 -3001) + 0.05 ( 17 000-5001) + 0.0575 ( 50 000 - 17 001) =  60+ 59.97+599.95 + 1897.44 =  2617.36

tax is = 2617.36

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3 years ago
Wastewater is filling barrels at the rate of 11 quarts per hour. The recycling facility picks up 120 full barrels on each trip,
Pepsi [2]
11t=120(12)

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3 years ago
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Dahasolnce [82]
Times by 3. Then divide the top backup by 3 to get 9/30. 9/30+9/30+9/30=27/30=9/10.
3 0
3 years ago
What measures of a cylinder can be determined when given the volume and the height? Describe how to find the measure.
Maru [420]

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Step-by-step explanation:

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I'll proceed by evaluating total length and surface area by scanned images. For measurements, I suggest to use winrhizo or any similar software. In this case the most important thing to think about is to use the appropiate acquisition parameters, I mean, to set a good resolution during scanning. Pixels of the aquired image should be smaller than root hairs diameter. Therefore, let me try to suggest you a good acquisition resolution. Making a quick research, it seems that hair root diameters range between 0,012 and 0,017 mm, so I suggest a resolution that will give a pixel dimension of 0,002 mm. Root hair diameters should be composed by 6-8 pixels, that is enough for winrhizo measurements. Resolution is measured in dpi, so in "dots/pixel per inch". A inch is 25,4 mm. We need pixels with a diameter of 0,002 mm, so in 25,4 mm we found 12700 pixels. That means 12700 dpi. It's a very high resolution, you need a good scanner and much space in your computer.
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