cross multiply the equation to give you
1= a(2bh+3)
divide both sides by a(2b+3)
answer is 1/2ab+3 = h
Answer:
Yes. For example, a hotel advertises, “Buy 4 nights, get the 5th night free.” Taking advantage of the deal, a customer purchases 5 nights for $400. Each night of the customer’s 5-night stay is subject to the fee.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given
![6x_1-9x_2=8](https://tex.z-dn.net/?f=6x_1-9x_2%3D8)
![9x_1+kx_2=-1](https://tex.z-dn.net/?f=9x_1%2Bkx_2%3D-1)
The given system is
can be represented by
![\begin{bmatrix}6 &-9 \\ 9 & k\end{bmatrix}\begin{bmatrix}x_1\\ x_2\end{bmatrix}=\begin{bmatrix}8\\ -1\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D6%20%26-9%20%5C%5C%209%20%26%20k%5Cend%7Bbmatrix%7D%5Cbegin%7Bbmatrix%7Dx_1%5C%5C%20x_2%5Cend%7Bbmatrix%7D%3D%5Cbegin%7Bbmatrix%7D8%5C%5C%20-1%5Cend%7Bbmatrix%7D)
The given system is consistent when determinant of A is not equal to zero
![|A|](https://tex.z-dn.net/?f=%7CA%7C)
![|A|=6k-(-81)=6k+81](https://tex.z-dn.net/?f=%7CA%7C%3D6k-%28-81%29%3D6k%2B81)
![k\neq \frac{-27}{2}](https://tex.z-dn.net/?f=k%5Cneq%20%5Cfrac%7B-27%7D%7B2%7D)
i.e. system is consistent for all value of k except ![k=\frac{-27}{2}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B-27%7D%7B2%7D)
![R-\frac{-27}{2}](https://tex.z-dn.net/?f=R-%5Cfrac%7B-27%7D%7B2%7D)
Answer:
2
Step-by-step explanantion:
You sustitute 20 for s to get 20 = d + 18, subtract 18 from both sides and you get d = 2.
Answer:
No, his value of (negative 4) squared should be positive because an even exponent indicates a positive value.
Step-by-step explanation:
Don't have one. I took the test.