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mart [117]
3 years ago
15

Please someone help me !!!!!

Mathematics
1 answer:
Sveta_85 [38]3 years ago
6 0
X² = 16
x = ±√16
x = <span>±4

</span>The roots of this equation are -4 and 4
<span>Сorrect answer is third from above</span>
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Consider the function attached below
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2

Step-by-step explanation:

Hello,

x=(fof^{-1})(x)=f(f^{-1}(x))=\sqrt{2f^{-1}(x)}+5\\\sqrt{2f^{-1}(x)} =x-5\\2f^{-1}(x)=(x-5)^2\\f^{-1}(x)=\dfrac{(x-5)^2}{2}

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Find the equation of the line parallel to y=2x+1 that contains point (14,3)
Sophie [7]

First of all, remember what the equation of a line is:

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Given this information, we can start by plugging in what we know, we are given the slope which is 2 so we can fill that in, remember m=slope

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To find b, think about what your (x,y) point means:<span>(14,3). When x of the line is 14, y of the line must be 3.

Because we were given the point (14,3) 
</span>

We need to find the value of b.  The 2 is already set and x and y are variables. We want the equation for the line that specifically passes through the given point (14,3).

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solving for b: b=3-(2)(14). b=-25.

<span>Plug that in for b: 
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<span>Final answer: 
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</span></span>
8 0
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