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Sphinxa [80]
3 years ago
8

The formula for the area A of a trapezoid is A=1/2(b1+b2)h, where b1 and b2 represents the lengths of the bases and h represents

the height. Which equation can be used to find the height of a trapezoid?
A. h=2A-b1-b2
B. h=2A/b1+b2
C. h=A(b1+b2)/2
D. h=A-2/b1-b2

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

B. h=2A/(b1+b2) . . . . parentheses are needed

Step-by-step explanation:

Multiply the equation by the inverse of the coefficient of h. That coefficient is (b1 +b2)/2, so its inverse is 2/(b1 +b2). Parentheses are needed.

... 2A/(b1 +b2) = h

_____

<em>Comment on the answer choices</em>

As written, <em>none of them are correct</em>. The denominator can only be written without parentheses if the division bar is horizontal, and so serves also as a grouping symbol.

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To calculate the distance between two points we use this formula:

\boxed{ \boxed{{d \:  =   \:  \sqrt{(x_2 \:  -  \: x_1)^{2} \:  +  \: (y_2 \:  -  \: y_1)^{2} } }}}

<h3>______________________</h3>

<h3>We organize the values:</h3>

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______________________

We apply the values already obtained to the formula to get the distance:

d \:  =   \:  \sqrt{( - 3 \:  -  \:( - 5))^{2} \:  +  \: (0 \:  -  \: 8)^{2} }

d \:  =   \:  \sqrt{( - 3 \:  -  \: ( - 5))^{2} \:  +  \: ( - 8)^{2} }

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d \:  =  \:  \sqrt{ {2}^{2} \:  +  \: 64 }

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d \:  =  \:  \sqrt{68}

d \:  = \boxed{ \bold{  \: 2 \sqrt{17}  \:   units}}

<h2>Answer: </h2>

\huge{\boxed{ \bold{2 \sqrt{17} \: units }}}

<h3><em><u>MissSpanish</u></em></h3>
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