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kirill115 [55]
3 years ago
6

Jan received -22 points on her exam. She got 11 questions wrong out of 50 questions. How much did Jan penalizedfor each wrong an

swer?
Mathematics
1 answer:
hammer [34]3 years ago
6 0
She was penalized 2 points a question
You might be interested in
Please explain every step
pogonyaev
<h3>Answer:</h3>

761680

<h3>Explanation:</h3>

\sf \boxed{\sum _{n=1}^{44}\:60\left(1.2\right)^{n-2}}

<u>Identify the following's</u>:

First Term [a]  =  60(1.2)ⁿ⁻² = 60(1.2)¹⁻² = 50

Common ratio [r]  =  1.2

Total Terms [n] =  44

===========================

\sf Geometric \ Sum \ of  \ Terms = \dfrac{a(r^n - 1)}{r-1}

===========================

Solving Steps:

<em />\rightarrow \sf \dfrac{a(r^n - 1)}{r-1}<em />

<em />

<em />\rightarrow \sf \dfrac{50(1.2^{44} - 1)}{1.2-1}<em />

<em />

<em />\rightarrow \sf 761679.5808<em />

<em />

\rightarrow \sf 761680 \ \ \  (rounded \ to \ nearest \ integer)

8 0
2 years ago
Solve for x. -2(16 - 4x) - 8 = 6(x + 2)
VARVARA [1.3K]
-32 + 8x - 8 = 6x + 12
8x - 40 = 6x + 12
8x = 6x + 12 + 40
8x = 6x + 52
8x - 6x = 52
2x = 52
x = 52/2
x = 26
3 0
3 years ago
Pls help :)) this question is confusing for me :)
Temka [501]

Given:

y^{2}(2 y-5)-8 y+20

To find:

The product of the expression.

Solution:

y^{2}(2 y-5)-8 y+20=y^{2}(2 y-5)+(-8 y+20)

Take out -4 as a common factor in Last two terms.

                                =y^{2}(2 y-5)-4(2 y-5)

Make sure the terms in both brackets must be same.

Take out common factor (2y - 5) from both terms.

                                =(2 y-5)(y^{2}-4)

4 can be written as 2².

                                =(2 y-5)\left(y^{2}-2^2\right)

Using the identity: (a^2-b^2)=(a-b)(a+b)

                                =(2 y-5)(y-2)(y+2).

The product is (2 y-5)(y-2)(y+2).

5 0
3 years ago
Help me please i don't understand this...
OLga [1]

Answer:

Both of them are correct.

The table and the graph given is correct.

3 0
3 years ago
Read 2 more answers
Oi tu bem com voces eu sou novo oiiiiii
True [87]

Answer:

Please post useful questions thanks!

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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