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2 years ago

Area of Rectangles and Squares. Please show the work, I need help

Mathematics

2 answers:

USPshnik [31]2 years ago

7 0

Here, I think I can help you out:

1. 21 ÷ 3

= 7

Therefore, the length is 7cm².

2. 35 ÷ 7

= 5cm²

- And so on. Simply divide the area by the length of the side given; you can answer up to question six using this strategy.

7. All sides of a square are the same length.

7 x 7

= 49cm²

9. 2 x 3.5

= 7m²

- The formula to find the area of a square/rectangle is length x width. Just multiply the given lengths for the answers :)

spayn [35]2 years ago

5 0

Step-by-step explanation:

Q.1 Solutions

1. Area of rectangle= L×B

21=L×3

21/3=L

7cm Answer

2. Area of square=S×S

35m²=S×7m

35/7=S

5=S

5m Answer

3. Area of rectangle= L×B

5%m²=L×½m

5/½=L

2.5=L

2.5m Answer

4. Area of square= S×S

120mm²=S×10mm

120/10=S

12=S

12mm Answer

5. Area of rectangle= L×B

7%m²=L×1%m

7/1=L

7=L

7m Answer

6. Area of square=S×S

15cm²=S×6cm

15/6=S

2.5=S

2.5cm Answer...

Q.2 Solutions

Note: you might be knowing the formulas so please understand this:

7.49cm

8.400cm

10.86cm

11.40m

12.244m

13.1600m

14.120cm

15.134m

hope it helps!!!!! :) :)

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A two digit number when read from left to right to right consiststs of consecutive integers. the nmber is six more than for time

Solnce55 [7]

I suppose you want to know such number. Since we have a two digit number consisting of two consecutive integers, the only possible numbers are:

$12,23,34,45,56,67,78,89$

Since we sorted all the cases out, we simply have to check which one satisfies the requirement. For each number, we'll write four times the the sum of its digits, and add 6, hoping to get the original number.

$\text{Number: } 12,\ \ 4\times \text{sum of digits: } 12\ \ \text{plus six: } 18\neq 12$

$\text{Number: } 23,\ \ 4\times \text{sum of digits: } 24\ \ \text{plus six: } 30\neq 23$

$\text{Number: } 34,\ \ 4\times \text{sum of digits: } 28\ \ \text{plus six: } 34$

So, the answer is 34.

3 0

3 years ago

The number of mosquitoes at the beach has increased by 50% every year since 2012. In 2012, there were 2,500 mosquitoes. How many

xxTIMURxx [149]

Answer:

Step-by-step explanation:

2012 = 2500

2500 x .50 = 1250

2500 + 1250

2013 = 3750

3750 x .50 =

3750 + 1875

2014 = 5625

5625 x .50 = 2812.5

5625 + 2812.5

2015= 8437.5

8437.5 x .50 = 4218.75

8437.5 + 4218.75

2016= 12656.25

12656.25 x .50 = 6328.125

12656.25 + 6328.125

2017= 18984.375

18984.375 x .50 = 9492.1875

18984.375 + 9492.1875

2018= 28,476.5625‬

3 0

2 years ago

a right triangle is removed from a rectangle to create the shaded region shown below. find the area of the shaded region. be sur

ser-zykov [4K]

Answer:

Step-by-step explanation:

Objective: Find missing dimensions of the right triangle using the then subtract that area of the triangle from the rectangle's area.

Using the definition of a rectangle, the left vertical side measure is 7 and right vertical side is 6. So the missing legs of the triangle is 4 and 3.

Apply triangle formula, base x height divided by 2.

$\frac{4 \times 3}{2} = 6$

Area of rectangle is length x width so the area is

$7 \times 6 = 42$

Subtract 6 from 42.

$42 - 6 = 36$

3 0

2 years ago

Solve for x

Mademuasel [1]

Answer:

x = 9

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ ⇔ $a^{(m+n)}$

Given

$11^{x}$ = $11^{4}$ × $11^{5}$ = $11^{(4+5)}$ = $11^{9}$

Since the bases on both sides are common, then equate the exponents

x = 9

4 0

2 years ago

Please help me with this question!

gavmur [86]

First off, let's convert the percentages to decimal format, so our 77% turns to 77/100 or 0.77, and our 55% turns to 55/100 or 0.55 and so on

now, the sum of both salines, must add up to the 77% mixture, let's say is "y"
so, 11 + 4 = y, and whatever the concentration level is, must also sum up to the mixture's concentration of 77%

anyway thus

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{first sol'n}&11&x&11x\\
\textit{second sol'n}&4&0.55&2.20\\
------&-----&-------&-------\\
mixture&y&0.77&0.77y
\end{array}\\\\
-------------------------------\\\\
\begin{cases}
11+4=y\implies 15=\boxed{y}\\
11x+2.2=0.77y\\
----------\\
11x+2.2=0.77\cdot \boxed{15}
\end{cases}$

solve for "x"

6 0

3 years ago